com.google.gson.internal.LinkedTreeMap cannot be cast to my class
JavaJsonCastingGsonJava Problem Overview
I have some problems with getting my object from a JSON string.
I got the class Product
public class Product {
private String mBarcode;
private String mName;
private String mPrice;
public Product(String barcode, String name, String price) {
mBarcode = barcode;
mName = name;
mPrice = price;
}
public int getBarcode() {
return Integer.parseInt(mBarcode);
}
public String getName() {
return mName;
}
public double getPrice() {
return Double.parseDouble(mPrice);
}
}
From my server I get an ArrayList<Product>
in JSON String representation. For example:
[{"mBarcode":"123","mName":"Apfel","mPrice":"2.7"},{"mBarcode":"456","mName":"Pfirsich","mPrice":"1.1111"},{"mBarcode":"89325982","mName":"Birne","mPrice":"1.5555"}]
This String is generated like this:
public static <T> String arrayToString(ArrayList<T> list) {
Gson g = new Gson();
return g.toJson(list);
}
To get my Object back I use this function:
public static <T> ArrayList<T> stringToArray(String s) {
Gson g = new Gson();
Type listType = new TypeToken<ArrayList<T>>(){}.getType();
ArrayList<T> list = g.fromJson(s, listType);
return list;
}
But when calling
String name = Util.stringToArray(message).get(i).getName();
I get the error com.google.gson.internal.LinkedTreeMap cannot be cast to object.Product
What am I doing wrong? It looks like it created a List of LinkedTreeMaps but how do i convert those into my Product Object?
Java Solutions
Solution 1 - Java
In my opinion, due to type erasure, the parser can't fetch the real type T at runtime. One workaround would be to provide the class type as parameter to the method.
Something like this works, there are certainly other possible workarounds but I find this one very clear and concise.
public static <T> List<T> stringToArray(String s, Class<T[]> clazz) {
T[] arr = new Gson().fromJson(s, clazz);
return Arrays.asList(arr); //or return Arrays.asList(new Gson().fromJson(s, clazz)); for a one-liner
}
And call it like:
String name = stringToArray(message, Product[].class).get(0).getName();
Solution 2 - Java
I also had problems with GSON complaining about casting LinkedTreeMaps.
The answer provided by Alexis and the comment by Aljoscha explains why the error occurs; "Generics on a type are typically erased at runtime." My issue was that my code worked when I ran it normally, but using ProGuard caused code to be stripped that was vital to casting.
You can follow Alexis's answer and more clearly define the cast and that should fix the problems. You can also add the ProGuard rules given by Google (simply doing this cleared the issue up for me).
##---------------Begin: proguard configuration for Gson ----------
# Gson uses generic type information stored in a class file when working with fields. Proguard
# removes such information by default, so configure it to keep all of it.
-keepattributes Signature
# For using GSON @Expose annotation
-keepattributes *Annotation*
# Gson specific classes
-keep class sun.misc.Unsafe { *; }
#-keep class com.google.gson.stream.** { *; }
# Application classes that will be serialized/deserialized over Gson
-keep class com.google.gson.examples.android.model.** { *; }
##---------------End: proguard configuration for Gson ----------
Moral of the Story: Always check to see what ProGuard rules you need.
Solution 3 - Java
Similar to Alexis C's answers. but in Kotlin.
Just pass the class type into function and clarify what generic type is.
Here is simplified example.
inline fun <reified T> parseArray(json: String, typeToken: Type): T {
val gson = GsonBuilder().create()
return gson.fromJson<T>(json, typeToken)
}
Here is example call
fun test() {
val json: String = "......."
val type = object : TypeToken<List<MyObject>>() {}.type
val result: List<MyObject> = parseArray<List<MyObject>>(json = json, typeToken = type)
println(result)
}
Solution 4 - Java
If you use your own ArrayList<MyObject>
in gson when parsing;
Type typeMyType = new TypeToken<ArrayList<MyObject>>(){}.getType();
ArrayList<MyObject> myObject = gson.fromJson(jsonString, typeMyType)
Solution 5 - Java
I also faced class cast exception of com.google.gson.internal.LinkedTreeMap for my signed build only. I added these below lines in progurard. Then it works fine.
-keepattributes Signature
-keepattributes *Annotation*
-keep class com.google.** { *; }
-keep class sun.misc.** { *; }
Solution 6 - Java
For JSON
{
results: [
{
id: "10",
phone: "+91783XXXX345",
name: "Mr Example",
email: "[email protected]"
},
{
id: "11",
phone: "+9178XXXX66",
name: "Mr Foo",
email: "[email protected]"
}],
statusCode: "1",
count: "2"
}
In listView BaseAdapter file we need to map data using LinkedTreeMap Key Value object to get row attribute value as below:
...
...
@Override
public View getView(final int i, View view, ViewGroup viewGroup) {
if(view==null)
{
view= LayoutInflater.from(c).inflate(R.layout.listview_manage_clients,viewGroup,false);
}
TextView mUserName = (TextView) view.findViewById(R.id.userName);
TextView mUserPhone = (TextView) view.findViewById(R.id.userPhone);
Object getrow = this.users.get(i);
LinkedTreeMap<Object,Object> t = (LinkedTreeMap) getrow;
String name = t.get("name").toString();
mUserName.setText("Name is "+name);
mUserPhone.setText("Phone is "+phone);
return view;
}
...
...
Solution 7 - Java
use this when parsing
public static <T> List<T> parseGsonArray(String json, Class<T[]> model) {
return Arrays.asList(new Gson().fromJson(json, model));
}
Solution 8 - Java
I had the same problem. I noticed it only occures when you have List
My solution is to wrap the list in another Object:
class YourObjectList {
private List<YourObject> items;
// constructor, getter and setter
}
With that single object, i had no more problems with class cast exception.
Solution 9 - Java
{"root":
[
{"mBarcode":"123","mName":"Apfel","mPrice":"2.7"},
{"mBarcode":"456","mName":"Pfirsich","mPrice":"1.1111"},
{"mBarcode":"89325982","mName":"Birne","mPrice":"1.5555"}
]
}
JsonObject root = g.fromJson(json, JsonObject.class);
//read root element which contains list
JsonElement e = root.get("root");
//as the element is array convert it
JsonArray ja = e.getAsJsonArray();
for(JsonElement j : ja){
//here use the json to parse into your custom object
}
Solution 10 - Java
To add to the answers already mentioned here, if you have a generic class that handles, say, HTTP calls, it maybe useful to pass Class<T>
as part of the constructor.
To give a little more detail, this happens because Java cannot infer the Class<T>
during runtime with just T
. It needs the actual solid class to make the determination.
So, if you have something like this, like I do:
class HttpEndpoint<T> implements IEndpoint<T>
you can allow the inheriting code to also send the class<T>
, since at that point is it clear what T is.
public HttpEndpoint(String baseurl, String route, Class<T> cls) {
this.baseurl = baseurl;
this.route = route;
this.cls = cls;
}
inheriting class:
public class Players extends HttpEndpoint<Player> {
public Players() {
super("http://127.0.0.1:8080", "/players", Player.class);
}
}
while not entirely a clean solution, it does keep the code packaged up and you don't have to Class<T>
between methods.