Clone an image in cv2 python
PythonOpencvPython Problem Overview
I'm new to opencv, here is a question, what is the python function which act the same as cv::clone() in cpp? I just try to get a rect by
rectImg = img[10:20, 10:20]
but when I draw a line on it ,I find the line appear both on img and the rectImage,so , how can I get this done?
Python Solutions
Solution 1 - Python
The first answer is correct but you say that you are using cv2 which inherently uses numpy arrays. So, to make a complete different copy of say "myImage":
newImage = myImage.copy()
The above is enough. No need to import numpy.
Solution 2 - Python
If you use cv2, correct method is to use .copy() method in Numpy. It will create a copy of the array you need. Otherwise it will produce only a view of that object.
eg:
In [1]: import numpy as np
In [2]: x = np.arange(10*10).reshape((10,10))
In [4]: y = x[3:7,3:7].copy()
In [6]: y[2,2] = 1000
In [8]: 1000 in x
Out[8]: False # see, 1000 in y doesn't change values in x, parent array.
Solution 3 - Python
Using python 3 and opencv-python version 4.4.0, the following code should work:
img_src = cv2.imread('image.png')
img_clone = img_src.copy()
Solution 4 - Python
You can simply use Python standard library. Make a shallow copy of the original image as follows:
import copy
original_img = cv2.imread("foo.jpg")
clone_img = copy.copy(original_img)
Solution 5 - Python
My favorite method uses cv2.copyMakeBorder with no border, like so.
copy = cv2.copyMakeBorder(original,0,0,0,0,cv2.BORDER_REPLICATE)