Can You Get A Users Local LAN IP Address Via JavaScript?
JavascriptIp AddressJavascript Problem Overview
I know the initial reaction to this question is "no" and "it can't be done" and "you shouldn't need it, you are doing something wrong". What I'm trying to do is get the users LAN IP address, and display it on the web page. Why? Because that's what the page I'm working on is all about, showing as much information as possible about you, the visitor: https://www.whatsmyip.org/more-info-about-you/
So I'm not actually DOING anything with the IP, other than showing it to the user for informational purposes. I used to do this by using a small Java applet. It worked pretty well. But these days, browser make you hit agree and trust so many times, to run even the most minor java applet, that I'd rather not run one at all.
So for a while I just got rid of this feature, but I'd like it back if possible. It was something that I, as a computer consultant, would actually use from time to time. It's faster to go to this website to see what IP range a network is running on, than it is to go into System Preferences, Networking, and then whatever interface is active.
So I'm wondering, hoping, if there's some way to do it in javascript alone? Maybe some new object you can access, similar to the way javascript can ask the browser where is geographic location on earth is. Maybe theres something similar for client networking information? If not, perhaps theres some other way entirely to do it? The only ways I can think of are a java applet, or a flash object. I'd rather not do either of those.
Javascript Solutions
Solution 1 - Javascript
As it turns out, the recent WebRTC extension of HTML5 allows javascript to query the local client IP address. A proof of concept is available here: http://net.ipcalf.com
This feature is apparently by design, and is not a bug. However, given its controversial nature, I would be cautious about relying on this behaviour. Nevertheless, I think it perfectly and appropriately addresses your intended purpose (revealing to the user what their browser is leaking).
Solution 2 - Javascript
Update
This solution would not longer work because browsers are fixing webrtc leak: for more info on that read this other question: https://stackoverflow.com/questions/56755747/rtcicecandidate-no-longer-returning-ip
In addition to afourney's answer this code works in browsers that support WebRTC (Chrome and Firefox). I heard there is a movement going on to implement a feature that makes sites request the IP (like in case of user's geo-location or user-media) though it has yet to be implemented in either of those browsers.
Here is a modified version of the source code, reduced the lines, not making any stun requests since you only want Local IP not the Public IP:
window.RTCPeerConnection = window.RTCPeerConnection || window.mozRTCPeerConnection || window.webkitRTCPeerConnection;//compatibility for Firefox and chrome
var pc = new RTCPeerConnection({iceServers:[]}), noop = function(){};
pc.createDataChannel('');//create a bogus data channel
pc.createOffer(pc.setLocalDescription.bind(pc), noop);// create offer and set local description
pc.onicecandidate = function(ice)
{
if (ice && ice.candidate && ice.candidate.candidate)
{
var myIP = /([0-9]{1,3}(\.[0-9]{1,3}){3}|[a-f0-9]{1,4}(:[a-f0-9]{1,4}){7})/.exec(ice.candidate.candidate)[1];
console.log('my IP: ', myIP);
pc.onicecandidate = noop;
}
};
We are creating a dummy peer connection for the remote peer to contact us. We generally exchange ice candidates with each other and reading the ice candidates we can tell the ip of the user.
You can find a demo at --> Demo
Solution 3 - Javascript
The WebRTC API can be used to retrieve the client's local IP.
However the browser may not support it, or the client may have disabled it for security reasons. In any case, one should not rely on this "hack" on the long term as it is likely to be patched in the future (see Cullen Fluffy Jennings's answer).
The ECMAScript 6 code below demonstrates how to do that.
/* ES6 */
const findLocalIp = (logInfo = true) => new Promise( (resolve, reject) => {
window.RTCPeerConnection = window.RTCPeerConnection
|| window.mozRTCPeerConnection
|| window.webkitRTCPeerConnection;
if ( typeof window.RTCPeerConnection == 'undefined' )
return reject('WebRTC not supported by browser');
let pc = new RTCPeerConnection();
let ips = [];
pc.createDataChannel("");
pc.createOffer()
.then(offer => pc.setLocalDescription(offer))
.catch(err => reject(err));
pc.onicecandidate = event => {
if ( !event || !event.candidate ) {
// All ICE candidates have been sent.
if ( ips.length == 0 )
return reject('WebRTC disabled or restricted by browser');
return resolve(ips);
}
let parts = event.candidate.candidate.split(' ');
let [base,componentId,protocol,priority,ip,port,,type,...attr] = parts;
let component = ['rtp', 'rtpc'];
if ( ! ips.some(e => e == ip) )
ips.push(ip);
if ( ! logInfo )
return;
console.log(" candidate: " + base.split(':')[1]);
console.log(" component: " + component[componentId - 1]);
console.log(" protocol: " + protocol);
console.log(" priority: " + priority);
console.log(" ip: " + ip);
console.log(" port: " + port);
console.log(" type: " + type);
if ( attr.length ) {
console.log("attributes: ");
for(let i = 0; i < attr.length; i += 2)
console.log("> " + attr[i] + ": " + attr[i+1]);
}
console.log();
};
} );
Notice I write return resolve(..) or return reject(..) as a shortcut. Both of those functions do not return anything.
Then you may have something this :
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Local IP</title>
</head>
<body>
<h1>My local IP is</h1>
<p id="ip">Loading..</p>
<script src="ip.js"></script>
<script>
let p = document.getElementById('ip');
findLocalIp().then(
ips => {
let s = '';
ips.forEach( ip => s += ip + '<br>' );
p.innerHTML = s;
},
err => p.innerHTML = err
);
</script>
</body>
</html>
Solution 4 - Javascript
I cleaned up mido's post and then cleaned up the function that they found. This will either return false or an array. When testing remember that you need to collapse the array in the web developer console otherwise it's nonintuitive default behavior may deceive you in to thinking that it is returning an empty array.
function ip_local()
{
var ip = false;
window.RTCPeerConnection = window.RTCPeerConnection || window.mozRTCPeerConnection || window.webkitRTCPeerConnection || false;
if (window.RTCPeerConnection)
{
ip = [];
var pc = new RTCPeerConnection({iceServers:[]}), noop = function(){};
pc.createDataChannel('');
pc.createOffer(pc.setLocalDescription.bind(pc), noop);
pc.onicecandidate = function(event)
{
if (event && event.candidate && event.candidate.candidate)
{
var s = event.candidate.candidate.split('\n');
ip.push(s[0].split(' ')[4]);
}
}
}
return ip;
}
Additionally please keep in mind folks that this isn't something old-new like CSS border-radius though one of those bits that is outright not supported by IE11 and older. Always use object detection, test in reasonably older browsers (e.g. Firefox 4, IE9, Opera 12.1) and make sure your newer scripts aren't breaking your newer bits of code. Additionally always detect standards compliant code first so if there is something with say a CSS prefix detect the standard non-prefixed code first and then fall back as in the long term support will eventually be standardized for the rest of it's existence.
Solution 5 - Javascript
Chrome 76+
Last year I used Linblow's answer (2018-Oct-19) to successfully discover my local IP via javascript. However, recent Chrome updates (76?) have wonked this method so that it now returns an obfuscated IP, such as: 1f4712db-ea17-4bcf-a596-105139dfd8bf.local
If you have full control over your browser, you can undo this behavior by turning it off in Chrome Flags, by typing this into your address bar:
chrome://flags
and DISABLING the flag Anonymize local IPs exposed by WebRTC
In my case, I require the IP for a TamperMonkey script to determine my present location and do different things based on my location. I also have full control over my own browser settings (no Corporate Policies, etc). So for me, changing the chrome://flags setting does the trick.
Sources:
https://groups.google.com/forum/#!topic/discuss-webrtc/6stQXi72BEU
https://codelabs.developers.google.com/codelabs/webrtc-web/index.html
Solution 6 - Javascript
function getUserIP(onNewIP) { // onNewIp - your listener function for new IPs
//compatibility for firefox and chrome
var myPeerConnection = window.RTCPeerConnection || window.mozRTCPeerConnection || window.webkitRTCPeerConnection;
var pc = new myPeerConnection({
iceServers: []
}),
noop = function() {},
localIPs = {},
ipRegex = /([0-9]{1,3}(\.[0-9]{1,3}){3}|[a-f0-9]{1,4}(:[a-f0-9]{1,4}){7})/g,
key;
function iterateIP(ip) {
if (!localIPs[ip]) onNewIP(ip);
localIPs[ip] = true;
}
onNewIP
//create a bogus data channel
pc.createDataChannel("");
// create offer and set local description
pc.createOffer().then(function(sdp) {
sdp.sdp.split('\n').forEach(function(line) {
if (line.indexOf('candidate') < 0) return;
line.match(ipRegex).forEach(iterateIP);
});
pc.setLocalDescription(sdp, noop, noop);
}).catch(function(reason) {
// An error occurred, so handle the failure to connect
});
//listen for candidate events
pc.onicecandidate = function(ice) {
if (!ice || !ice.candidate || !ice.candidate.candidate || !ice.candidate.candidate.match(ipRegex)) return;
ice.candidate.candidate.match(ipRegex).forEach(iterateIP);
};
}
getUserIP(console.log)
Solution 7 - Javascript
You can find more info about what limitations browsers will likely add to mitigate this and what IETF is doing about it as well as why this is needed at IETF SPEC on IP handling
Solution 8 - Javascript
> Now supported in internal-ip!
An RTCPeerConnection can be used. In browsers like Chrome where a getUserMedia permission is required, we can just detect available input devices and request for them.
const internalIp = async () => {
if (!RTCPeerConnection) {
throw new Error("Not supported.")
}
const peerConnection = new RTCPeerConnection({ iceServers: [] })
peerConnection.createDataChannel('')
peerConnection.createOffer(peerConnection.setLocalDescription.bind(peerConnection), () => { })
peerConnection.addEventListener("icecandidateerror", (event) => {
throw new Error(event.errorText)
})
return new Promise(async resolve => {
peerConnection.addEventListener("icecandidate", async ({candidate}) => {
peerConnection.close()
if (candidate && candidate.candidate) {
const result = candidate.candidate.split(" ")[4]
if (result.endsWith(".local")) {
const inputDevices = await navigator.mediaDevices.enumerateDevices()
const inputDeviceTypes = inputDevices.map(({ kind }) => kind)
const constraints = {}
if (inputDeviceTypes.includes("audioinput")) {
constraints.audio = true
} else if (inputDeviceTypes.includes("videoinput")) {
constraints.video = true
} else {
throw new Error("An audio or video input device is required!")
}
const mediaStream = await navigator.mediaDevices.getUserMedia(constraints)
mediaStream.getTracks().forEach(track => track.stop())
resolve(internalIp())
}
resolve(result)
}
})
})
}
Solution 9 - Javascript
Try to use the OS package to find the wifi ip.
const os = require('os');
console.log('IP Address: ' + JSON.stringify(os.networkInterfaces()['Wi-Fi']).match(/"192.168.\d+.\d+"/g)[0])