Call laravel controller via command line

PhpLaravel

Php Problem Overview


In kohana framework I can call controller via command line using

php5 index.php --uri=controller/method/var1/var2

Is it possible to call controller I want in Laravel 5 via cli? If yes, how to do this?

Php Solutions


Solution 1 - Php

There is no way so far (not sure if there will ever be). However you can create your own Artisan Command that can do that. Create a command CallRoute using this:

php artisan make:console CallRoute

For Laravel 5.3 or greater you need to use make:command instead:

php artisan make:command CallRoute

This will generate a command class in app/Console/Commands/CallRoute.php. The contents of that class should look like this:

<?php namespace App\Console\Commands;

use Illuminate\Console\Command;
use Symfony\Component\Console\Input\InputOption;
use Illuminate\Http\Request;

class CallRoute extends Command {

	protected $name = 'route:call';
	protected $description = 'Call route from CLI';

	public function __construct()
	{
		parent::__construct();
	}

	public function fire()
	{
		$request = Request::create($this->option('uri'), 'GET');
		$this->info(app()['Illuminate\Contracts\Http\Kernel']->handle($request));
	}

	protected function getOptions()
	{
		return [
			['uri', null, InputOption::VALUE_REQUIRED, 'The path of the route to be called', null],
		];
	}

}

You then need to register the command by adding it to the $commands array in app/Console/Kernel.php:

protected $commands = [
	...,
	'App\Console\Commands\CallRoute',
];

You can now call any route by using this command:

php artisan route:call --uri=/route/path/with/param

Mind you, this command will return a response as it would be sent to the browser, that means it includes the HTTP headers at the top of the output.

Solution 2 - Php

I am using Laravel 5.0 and I am triggering controllers using this code:

$ php artisan tinker
$ $controller = app()->make('App\Http\Controllers\MyController');
$ app()->call([$controller, 'myMethodName'], []);

the last [] in the app()->call() can hold arguments such as [user_id] => 10 etc'

Solution 3 - Php

For Laravel 5.4: php artisan make:command CallRoute

Then in app/Console/Commands/CallRoute.php:

namespace App\Console\Commands;

use Illuminate\Console\Command;
use Illuminate\Http\Request;

class CallRoute extends Command
{
    /**
     * The name and signature of the console command.
     *
     * @var string
     */
    protected $signature = 'route:call {uri}';

    /**
     * The console command description.
     *
     * @var string
     */
    protected $description = 'php artsian route:call /route';

    /**
     * Create a new command instance.
     *
     * @return void
     */
    public function __construct()
    {
        parent::__construct();
    }

    /**
     * Execute the console command.
     *
     * @return mixed
     */
    public function handle()
    {
        $request = Request::create($this->argument('uri'), 'GET');
        $this->info(app()->make(\Illuminate\Contracts\Http\Kernel::class)->handle($request));
    }

}

Then in app/Console/Kernel.php:

protected $commands = [
    'App\Console\Commands\CallRoute'
];

Call like: php artisan route:call /path

Solution 4 - Php

You can do it in this way too. First, create the command using

php artisan command:commandName

Now in the handle of the command, call the controller and trigger the method. Eg,

public function handle(){
 $controller = new ControllerName(); // make sure to import the controller
 $controller->controllerMethod();
}

This will actually do the work. Hope, this helps.

DEPENDENCY INJECTION WON'T WORK

Solution 5 - Php

Laravel 5.7

Using tinker

 // URL: http://xxx.test/calendar?filter[id]=1&anotherparam=2
 $cc = app()->make('App\Http\Controllers\CalendarController');
 app()->call([$cc, 'getCalendarV2'], ['filter[id]'=>1, 'anotherparam' => '2']);

Solution 6 - Php

To version 8 of laravel.

First step: type command in terminal
php artisan tinker

Secound step:

$instante = new MyController(null);

Or if argument by an instance of model, then, pass name model class.
Example:

$instante = new MyController(new MyModelHere());

Press enter.

Finally, call method with $instante->myMethod() here.

See: enter image description here

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionuser3345632View Question on Stackoverflow
Solution 1 - PhpBogdanView Answer on Stackoverflow
Solution 2 - PhpBroshiView Answer on Stackoverflow
Solution 3 - PhpMatt HabermehlView Answer on Stackoverflow
Solution 4 - PhpKoushik DasView Answer on Stackoverflow
Solution 5 - PhpkenView Answer on Stackoverflow
Solution 6 - PhpTaffarel XavierView Answer on Stackoverflow