Calculating a directory's size using Python?
PythonDirectoryPython Problem Overview
Before I re-invent this particular wheel, has anybody got a nice routine for calculating the size of a directory using Python? It would be very nice if the routine would format the size nicely in Mb/Gb etc.
Python Solutions
Solution 1 - Python
This walks all sub-directories; summing file sizes:
import os
def get_size(start_path = '.'):
total_size = 0
for dirpath, dirnames, filenames in os.walk(start_path):
for f in filenames:
fp = os.path.join(dirpath, f)
# skip if it is symbolic link
if not os.path.islink(fp):
total_size += os.path.getsize(fp)
return total_size
print(get_size(), 'bytes')
And a oneliner for fun using os.listdir (Does not include sub-directories):
import os
sum(os.path.getsize(f) for f in os.listdir('.') if os.path.isfile(f))
Reference:
- os.path.getsize - Gives the size in bytes
- os.walk
- os.path.islink
Updated To use os.path.getsize, this is clearer than using the os.stat().st_size method.
Thanks to ghostdog74 for pointing this out!
os.stat - st_size Gives the size in bytes. Can also be used to get file size and other file related information.
import os
nbytes = sum(d.stat().st_size for d in os.scandir('.') if d.is_file())
Update 2018
If you use Python 3.4 or previous then you may consider using the more efficient walk
method provided by the third-party scandir
package. In Python 3.5 and later, this package has been incorporated into the standard library and os.walk
has received the corresponding increase in performance.
Update 2019
Recently I've been using pathlib
more and more, here's a pathlib
solution:
from pathlib import Path
root_directory = Path('.')
sum(f.stat().st_size for f in root_directory.glob('**/*') if f.is_file())
Solution 2 - Python
Some of the approaches suggested so far implement a recursion, others employ a shell or will not produce neatly formatted results. When your code is one-off for Linux platforms, you can get formatting as usual, recursion included, as a one-liner. Except for the print
in the last line, it will work for current versions of python2
and python3
:
du.py
-----
#!/usr/bin/python3
import subprocess
def du(path):
"""disk usage in human readable format (e.g. '2,1GB')"""
return subprocess.check_output(['du','-sh', path]).split()[0].decode('utf-8')
if __name__ == "__main__":
print(du('.'))
is simple, efficient and will work for files and multilevel directories:
$ chmod 750 du.py
$ ./du.py
2,9M
Solution 3 - Python
Here is a recursive function (it recursively sums up the size of all subfolders and their respective files) which returns exactly the same bytes as when running "du -sb ." in linux (where the "." means "the current folder"):
import os
def getFolderSize(folder):
total_size = os.path.getsize(folder)
for item in os.listdir(folder):
itempath = os.path.join(folder, item)
if os.path.isfile(itempath):
total_size += os.path.getsize(itempath)
elif os.path.isdir(itempath):
total_size += getFolderSize(itempath)
return total_size
print "Size: " + str(getFolderSize("."))
Solution 4 - Python
Python 3.5 recursive folder size using os.scandir
def folder_size(path='.'):
total = 0
for entry in os.scandir(path):
if entry.is_file():
total += entry.stat().st_size
elif entry.is_dir():
total += folder_size(entry.path)
return total
Solution 5 - Python
Using pathlib
I came up with this one-liner to get the size of a folder:
sum(file.stat().st_size for file in Path(folder).rglob('*'))
And this is what I came up with for a nicely formatted output:
from pathlib import Path
def get_folder_size(folder):
return ByteSize(sum(file.stat().st_size for file in Path(folder).rglob('*')))
class ByteSize(int):
_kB = 1024
_suffixes = 'B', 'kB', 'MB', 'GB', 'PB'
def __new__(cls, *args, **kwargs):
return super().__new__(cls, *args, **kwargs)
def __init__(self, *args, **kwargs):
self.bytes = self.B = int(self)
self.kilobytes = self.kB = self / self._kB**1
self.megabytes = self.MB = self / self._kB**2
self.gigabytes = self.GB = self / self._kB**3
self.petabytes = self.PB = self / self._kB**4
*suffixes, last = self._suffixes
suffix = next((
suffix
for suffix in suffixes
if 1 < getattr(self, suffix) < self._kB
), last)
self.readable = suffix, getattr(self, suffix)
super().__init__()
def __str__(self):
return self.__format__('.2f')
def __repr__(self):
return '{}({})'.format(self.__class__.__name__, super().__repr__())
def __format__(self, format_spec):
suffix, val = self.readable
return '{val:{fmt}} {suf}'.format(val=val, fmt=format_spec, suf=suffix)
def __sub__(self, other):
return self.__class__(super().__sub__(other))
def __add__(self, other):
return self.__class__(super().__add__(other))
def __mul__(self, other):
return self.__class__(super().__mul__(other))
def __rsub__(self, other):
return self.__class__(super().__sub__(other))
def __radd__(self, other):
return self.__class__(super().__add__(other))
def __rmul__(self, other):
return self.__class__(super().__rmul__(other))
Usage:
>>> size = get_folder_size("c:/users/tdavis/downloads")
>>> print(size)
5.81 GB
>>> size.GB
5.810891855508089
>>> size.gigabytes
5.810891855508089
>>> size.PB
0.005674699077644618
>>> size.MB
5950.353260040283
>>> size
ByteSize(6239397620)
I also came across this question, which has some more compact and probably more performant strategies for printing file sizes.
Solution 6 - Python
for python3.5+
from pathlib import Path
def get_size(folder: str) -> int:
return sum(p.stat().st_size for p in Path(folder).rglob('*'))
Usage::
In [6]: get_size('/etc/not-exist-path')
Out[6]: 0
In [7]: get_size('.')
Out[7]: 12038689
In [8]: def filesize(size: int) -> str:
...: for unit in ("B", "K", "M", "G", "T"):
...: if size < 1024:
...: break
...: size /= 1024
...: return f"{size:.1f}{unit}"
...:
In [9]: filesize(get_size('.'))
Out[9]: '11.5M'
Solution 7 - Python
monknut answer is good but it fails on broken symlink, so you also have to check if this path really exists
if os.path.exists(fp):
total_size += os.stat(fp).st_size
Solution 8 - Python
The accepted answer doesn't take into account hard or soft links, and would count those files twice. You'd want to keep track of which inodes you've seen, and not add the size for those files.
import os
def get_size(start_path='.'):
total_size = 0
seen = {}
for dirpath, dirnames, filenames in os.walk(start_path):
for f in filenames:
fp = os.path.join(dirpath, f)
try:
stat = os.stat(fp)
except OSError:
continue
try:
seen[stat.st_ino]
except KeyError:
seen[stat.st_ino] = True
else:
continue
total_size += stat.st_size
return total_size
print get_size()
Solution 9 - Python
a recursive one-liner:
def getFolderSize(p):
from functools import partial
prepend = partial(os.path.join, p)
return sum([(os.path.getsize(f) if os.path.isfile(f) else getFolderSize(f)) for f in map(prepend, os.listdir(p))])
Solution 10 - Python
Chris' answer is good but could be made more idiomatic by using a set to check for seen directories, which also avoids using an exception for control flow:
def directory_size(path):
total_size = 0
seen = set()
for dirpath, dirnames, filenames in os.walk(path):
for f in filenames:
fp = os.path.join(dirpath, f)
try:
stat = os.stat(fp)
except OSError:
continue
if stat.st_ino in seen:
continue
seen.add(stat.st_ino)
total_size += stat.st_size
return total_size # size in bytes
Solution 11 - Python
A little late to the party but in one line provided that you have glob2 and humanize installed. Note that in Python 3, the default iglob
has a recursive mode. How to modify the code for Python 3 is left as a trivial exercise for the reader.
>>> import os
>>> from humanize import naturalsize
>>> from glob2 import iglob
>>> naturalsize(sum(os.path.getsize(x) for x in iglob('/var/**'))))
'546.2 MB'
Solution 12 - Python
For the second part of the question
def human(size):
B = "B"
KB = "KB"
MB = "MB"
GB = "GB"
TB = "TB"
UNITS = [B, KB, MB, GB, TB]
HUMANFMT = "%f %s"
HUMANRADIX = 1024.
for u in UNITS[:-1]:
if size < HUMANRADIX : return HUMANFMT % (size, u)
size /= HUMANRADIX
return HUMANFMT % (size, UNITS[-1])
Solution 13 - Python
You can do something like this :
import commands
size = commands.getoutput('du -sh /path/').split()[0]
in this case I have not tested the result before returning it, if you want you can check it with commands.getstatusoutput.
Solution 14 - Python
One-liner you say... Here is a one liner:
sum([sum(map(lambda fname: os.path.getsize(os.path.join(directory, fname)), files)) for directory, folders, files in os.walk(path)])
Although I would probably split it out and it performs no checks.
To convert to kb see https://stackoverflow.com/questions/1094841/reusable-library-to-get-human-readable-version-of-file-size and work it in
Solution 15 - Python
The following script prints directory size of all sub-directories for the specified directory. It also tries to benefit (if possible) from caching the calls of a recursive functions. If an argument is omitted, the script will work in the current directory. The output is sorted by the directory size from biggest to smallest ones. So you can adapt it for your needs.
PS i've used recipe 578019 for showing directory size in human-friendly format (http://code.activestate.com/recipes/578019/)
from __future__ import print_function
import os
import sys
import operator
def null_decorator(ob):
return ob
if sys.version_info >= (3,2,0):
import functools
my_cache_decorator = functools.lru_cache(maxsize=4096)
else:
my_cache_decorator = null_decorator
start_dir = os.path.normpath(os.path.abspath(sys.argv[1])) if len(sys.argv) > 1 else '.'
@my_cache_decorator
def get_dir_size(start_path = '.'):
total_size = 0
if 'scandir' in dir(os):
# using fast 'os.scandir' method (new in version 3.5)
for entry in os.scandir(start_path):
if entry.is_dir(follow_symlinks = False):
total_size += get_dir_size(entry.path)
elif entry.is_file(follow_symlinks = False):
total_size += entry.stat().st_size
else:
# using slow, but compatible 'os.listdir' method
for entry in os.listdir(start_path):
full_path = os.path.abspath(os.path.join(start_path, entry))
if os.path.isdir(full_path):
total_size += get_dir_size(full_path)
elif os.path.isfile(full_path):
total_size += os.path.getsize(full_path)
return total_size
def get_dir_size_walk(start_path = '.'):
total_size = 0
for dirpath, dirnames, filenames in os.walk(start_path):
for f in filenames:
fp = os.path.join(dirpath, f)
total_size += os.path.getsize(fp)
return total_size
def bytes2human(n, format='%(value).0f%(symbol)s', symbols='customary'):
"""
(c) http://code.activestate.com/recipes/578019/
Convert n bytes into a human readable string based on format.
symbols can be either "customary", "customary_ext", "iec" or "iec_ext",
see: http://goo.gl/kTQMs
>>> bytes2human(0)
'0.0 B'
>>> bytes2human(0.9)
'0.0 B'
>>> bytes2human(1)
'1.0 B'
>>> bytes2human(1.9)
'1.0 B'
>>> bytes2human(1024)
'1.0 K'
>>> bytes2human(1048576)
'1.0 M'
>>> bytes2human(1099511627776127398123789121)
'909.5 Y'
>>> bytes2human(9856, symbols="customary")
'9.6 K'
>>> bytes2human(9856, symbols="customary_ext")
'9.6 kilo'
>>> bytes2human(9856, symbols="iec")
'9.6 Ki'
>>> bytes2human(9856, symbols="iec_ext")
'9.6 kibi'
>>> bytes2human(10000, "%(value).1f %(symbol)s/sec")
'9.8 K/sec'
>>> # precision can be adjusted by playing with %f operator
>>> bytes2human(10000, format="%(value).5f %(symbol)s")
'9.76562 K'
"""
SYMBOLS = {
'customary' : ('B', 'K', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y'),
'customary_ext' : ('byte', 'kilo', 'mega', 'giga', 'tera', 'peta', 'exa',
'zetta', 'iotta'),
'iec' : ('Bi', 'Ki', 'Mi', 'Gi', 'Ti', 'Pi', 'Ei', 'Zi', 'Yi'),
'iec_ext' : ('byte', 'kibi', 'mebi', 'gibi', 'tebi', 'pebi', 'exbi',
'zebi', 'yobi'),
}
n = int(n)
if n < 0:
raise ValueError("n < 0")
symbols = SYMBOLS[symbols]
prefix = {}
for i, s in enumerate(symbols[1:]):
prefix[s] = 1 << (i+1)*10
for symbol in reversed(symbols[1:]):
if n >= prefix[symbol]:
value = float(n) / prefix[symbol]
return format % locals()
return format % dict(symbol=symbols[0], value=n)
############################################################
###
### main ()
###
############################################################
if __name__ == '__main__':
dir_tree = {}
### version, that uses 'slow' [os.walk method]
#get_size = get_dir_size_walk
### this recursive version can benefit from caching the function calls (functools.lru_cache)
get_size = get_dir_size
for root, dirs, files in os.walk(start_dir):
for d in dirs:
dir_path = os.path.join(root, d)
if os.path.isdir(dir_path):
dir_tree[dir_path] = get_size(dir_path)
for d, size in sorted(dir_tree.items(), key=operator.itemgetter(1), reverse=True):
print('%s\t%s' %(bytes2human(size, format='%(value).2f%(symbol)s'), d))
print('-' * 80)
if sys.version_info >= (3,2,0):
print(get_dir_size.cache_info())
Sample output:
37.61M .\subdir_b
2.18M .\subdir_a
2.17M .\subdir_a\subdir_a_2
4.41K .\subdir_a\subdir_a_1
----------------------------------------------------------
CacheInfo(hits=2, misses=4, maxsize=4096, currsize=4)
EDIT: moved null_decorator above, as user2233949 recommended
Solution 16 - Python
use library sh: the module du
does it:
pip install sh
import sh
print( sh.du("-s", ".") )
91154728 .
if you want to pass asterix, use glob
as described here.
to convert the values in human readables, use humanize:
pip install humanize
import humanize
print( humanize.naturalsize( 91157384 ) )
91.2 MB
Solution 17 - Python
Get directory size
Properties of the solution:
- returns both: the apparent size (number of bytes in the file) and the actual disk space the files uses.
- counts hard linked files only once
- counts symlinks the same way
du
does - does not use recursion
- uses
st.st_blocks
for disk space used, thus works only on Unix-like systems
The code:
import os
def du(path):
if os.path.islink(path):
return (os.lstat(path).st_size, 0)
if os.path.isfile(path):
st = os.lstat(path)
return (st.st_size, st.st_blocks * 512)
apparent_total_bytes = 0
total_bytes = 0
have = []
for dirpath, dirnames, filenames in os.walk(path):
apparent_total_bytes += os.lstat(dirpath).st_size
total_bytes += os.lstat(dirpath).st_blocks * 512
for f in filenames:
fp = os.path.join(dirpath, f)
if os.path.islink(fp):
apparent_total_bytes += os.lstat(fp).st_size
continue
st = os.lstat(fp)
if st.st_ino in have:
continue # skip hardlinks which were already counted
have.append(st.st_ino)
apparent_total_bytes += st.st_size
total_bytes += st.st_blocks * 512
for d in dirnames:
dp = os.path.join(dirpath, d)
if os.path.islink(dp):
apparent_total_bytes += os.lstat(dp).st_size
return (apparent_total_bytes, total_bytes)
Example usage:
>>> du('/lib')
(236425839, 244363264)
$ du -sb /lib
236425839 /lib
$ du -sB1 /lib
244363264 /lib
Human readable file size
Properties of the solution:
- Supports up to Yottabytes
- Supports SI Units or IEC Units
- Support custom suffixes
The code:
def humanized_size(num, suffix='B', si=False):
if si:
units = ['','K','M','G','T','P','E','Z']
last_unit = 'Y'
div = 1000.0
else:
units = ['','Ki','Mi','Gi','Ti','Pi','Ei','Zi']
last_unit = 'Yi'
div = 1024.0
for unit in units:
if abs(num) < div:
return "%3.1f%s%s" % (num, unit, suffix)
num /= div
return "%.1f%s%s" % (num, last_unit, suffix)
Example usage:
>>> humanized_size(236425839)
'225.5MiB'
>>> humanized_size(236425839, si=True)
'236.4MB'
>>> humanized_size(236425839, si=True, suffix='')
'236.4M'
Solution 18 - Python
for getting the size of one file, there is os.path.getsize()
>>> import os
>>> os.path.getsize("/path/file")
35L
its reported in bytes.
Solution 19 - Python
For what it's worth... the tree command does all of this for free:
tree -h --du /path/to/dir # files and dirs
tree -h -d --du /path/to/dir # dirs only
I love Python, but by far the simplest solution to the problem requires no new code.
Solution 20 - Python
It is handy:
import os
import stat
size = 0
path_ = ""
def calculate(path=os.environ["SYSTEMROOT"]):
global size, path_
size = 0
path_ = path
for x, y, z in os.walk(path):
for i in z:
size += os.path.getsize(x + os.sep + i)
def cevir(x):
global path_
print(path_, x, "Byte")
print(path_, x/1024, "Kilobyte")
print(path_, x/1048576, "Megabyte")
print(path_, x/1073741824, "Gigabyte")
calculate("C:\Users\Jundullah\Desktop")
cevir(size)
Output:
C:\Users\Jundullah\Desktop 87874712211 Byte
C:\Users\Jundullah\Desktop 85815148.64355469 Kilobyte
C:\Users\Jundullah\Desktop 83803.85609722137 Megabyte
C:\Users\Jundullah\Desktop 81.83970321994275 Gigabyte
Solution 21 - Python
Here is a one liner that does it recursively (recursive option available as of Python 3.5):
import os
import glob
print(sum(os.path.getsize(f) for f in glob.glob('**', recursive=True) if os.path.isfile(f))/(1024*1024))
Solution 22 - Python
def recursive_dir_size(path):
size = 0
for x in os.listdir(path):
if not os.path.isdir(os.path.join(path,x)):
size += os.stat(os.path.join(path,x)).st_size
else:
size += recursive_dir_size(os.path.join(path,x))
return size
I wrote this function which gives me accurate overall size of a directory, i tried other for loop solutions with os.walk but i don't know why the end result was always less than the actual size (on ubuntu 18 env). I must have done something wrong but who cares wrote this one works perfectly fine.
Solution 23 - Python
I'm using python 2.7.13 with scandir and here's my one-liner recursive function to get the total size of a folder:
from scandir import scandir
def getTotFldrSize(path):
return sum([s.stat(follow_symlinks=False).st_size for s in scandir(path) if s.is_file(follow_symlinks=False)]) + \
+ sum([getTotFldrSize(s.path) for s in scandir(path) if s.is_dir(follow_symlinks=False)])
>>> print getTotFldrSize('.')
1203245680
Solution 24 - Python
When size of the sub-directories is computed, it should update its parent's folder size and this will go on till it reaches the root parent.
The following function computes the size of the folder and all its sub-folders.
import os
def folder_size(path):
parent = {} # path to parent path mapper
folder_size = {} # storing the size of directories
folder = os.path.realpath(path)
for root, _, filenames in os.walk(folder):
if root == folder:
parent[root] = -1 # the root folder will not have any parent
folder_size[root] = 0.0 # intializing the size to 0
elif root not in parent:
immediate_parent_path = os.path.dirname(root) # extract the immediate parent of the subdirectory
parent[root] = immediate_parent_path # store the parent of the subdirectory
folder_size[root] = 0.0 # initialize the size to 0
total_size = 0
for filename in filenames:
filepath = os.path.join(root, filename)
total_size += os.stat(filepath).st_size # computing the size of the files under the directory
folder_size[root] = total_size # store the updated size
temp_path = root # for subdirectories, we need to update the size of the parent till the root parent
while parent[temp_path] != -1:
folder_size[parent[temp_path]] += total_size
temp_path = parent[temp_path]
return folder_size[folder]/1000000.0
Solution 25 - Python
A solution that works on Python 3.6 using pathlib.
from pathlib import Path
sum([f.stat().st_size for f in Path("path").glob("**/*")])
Solution 26 - Python
du
does not follow symlinks by default. No answer here make use of follow_symlinks=False
.
Here is an implementation which follows default behavior of du:
def du(path) -> int:
total = 0
for entry in os.scandir(path):
if entry.is_file(follow_symlinks=False):
total += entry.stat().st_size
elif entry.is_dir(follow_symlinks=False):
total += du(entry.path)
return total
Test:
class Test(unittest.TestCase):
def test_du(self):
root = '/tmp/du_test'
subprocess.run(['rm', '-rf', root])
test_utils.mkdir(root)
test_utils.create_file(root, 'A', '1M')
test_utils.create_file(root, 'B', '1M')
sub = '/'.join([root, 'sub'])
test_utils.mkdir(sub)
test_utils.create_file(sub, 'C', '1M')
test_utils.create_file(sub, 'D', '1M')
subprocess.run(['ln', '-s', '/tmp', '/'.join([root, 'link']), ])
self.assertEqual(4 << 20, util.du(root))
Solution 27 - Python
import os
def get_size(path = os.getcwd()):
print("Calculating Size: ",path)
total_size = 0
#if path is directory--
if os.path.isdir(path):
print("Path type : Directory/Folder")
for dirpath, dirnames, filenames in os.walk(path):
for f in filenames:
fp = os.path.join(dirpath, f)
# skip if it is symbolic link
if not os.path.islink(fp):
total_size += os.path.getsize(fp)
#if path is a file---
elif os.path.isfile(path):
print("Path type : File")
total_size=os.path.getsize(path)
else:
print("Path Type : Special File (Socket, FIFO, Device File)" )
total_size=0
bytesize=total_size
print(bytesize, 'bytes')
print(bytesize/(1024), 'kilobytes')
print(bytesize/(1024*1024), 'megabytes')
print(bytesize/(1024*1024*1024), 'gegabytes')
return total_size
x=get_size("/content/examples")
I'm sure this helps! For folders and files as well!
Solution 28 - Python
This script tells you which file is the biggest in the CWD and also tells you in which folder the file is. This script works for me on win8 and python 3.3.3 shell
import os
folder=os.cwd()
number=0
string=""
for root, dirs, files in os.walk(folder):
for file in files:
pathname=os.path.join(root,file)
## print (pathname)
## print (os.path.getsize(pathname)/1024/1024)
if number < os.path.getsize(pathname):
number = os.path.getsize(pathname)
string=pathname
## print ()
print (string)
print ()
print (number)
print ("Number in bytes")
Solution 29 - Python
Admittedly, this is kind of hackish and only works on Unix/Linux.
It matches du -sb .
because in effect this is a Python bash wrapper that runs the du -sb .
command.
import subprocess
def system_command(cmd):
""""Function executes cmd parameter as a bash command."""
p = subprocess.Popen(cmd,
stdout=subprocess.PIPE,
stderr=subprocess.PIPE,
shell=True)
stdout, stderr = p.communicate()
return stdout, stderr
size = int(system_command('du -sb . ')[0].split()[0])
Solution 30 - Python
I'm a little late (and new) here but I chose to use the subprocess module and the 'du' command line with Linux to retrieve an accurate value for folder size in MB. I had to use if and elif for root folder because otherwise subprocess raises error due to non-zero value returned.
import subprocess
import os
#
# get folder size
#
def get_size(self, path):
if os.path.exists(path) and path != '/':
cmd = str(subprocess.check_output(['sudo', 'du', '-s', path])).\
replace('b\'', '').replace('\'', '').split('\\t')[0]
return float(cmd) / 1000000
elif os.path.exists(path) and path == '/':
cmd = str(subprocess.getoutput(['sudo du -s /'])). \
replace('b\'', '').replace('\'', '').split('\n')
val = cmd[len(cmd) - 1].replace('/', '').replace(' ', '')
return float(val) / 1000000
else: raise ValueError
Solution 31 - Python
If you are in Windows OS you can do:
install the module pywin32 by launching:
pip install pywin32
and then coding the following:
import win32com.client as com
def get_folder_size(path):
try:
fso = com.Dispatch("Scripting.FileSystemObject")
folder = fso.GetFolder(path)
size = str(round(folder.Size / 1048576))
print("Size: " + size + " MB")
except Exception as e:
print("Error --> " + str(e))
Solution 32 - Python
Python 3.6+ recursive folder/file size using os.scandir
. As powerful as in the answer by @blakev, but shorter and in EAFP python style.
import os
def size(path, *, follow_symlinks=False):
try:
with os.scandir(path) as it:
return sum(size(entry, follow_symlinks=follow_symlinks) for entry in it)
except NotADirectoryError:
return os.stat(path, follow_symlinks=follow_symlinks).st_size
Solution 33 - Python
import os
def get_size(path):
total_size = 0
for dirpath, dirnames, filenames in os.walk(path):
for f in filenames:
if os.path.exists(fp):
fp = os.path.join(dirpath, f)
total_size += os.path.getsize(fp)
return total_size # in megabytes
Thanks monkut & troex!