Calculate size of files in shell

I'm trying to calculate the total size in bytes of all files (in a directory tree) matching a filename pattern just using the shell. This is what I have so far:

> find -name *.undo -exec stat -c%s {} ; | awk '{total += $1} END {print total}'

Is there an easier way to do this? I feel like there should be a simple du or find switch that does this for me but I can't find one.

To be clear I want to total files matching a pattern anywhere under a directory tree which means

> du -bs *.undo

won't work because it only matches the files in the current directory.

Try:

find . -name "*.undo" -ls | awk '{total += $7} END {print total}'

On my system the size of the file is the seventh field in the find -ls output. If your find … -ls output is different, adjust.

In this version, using the existing directory information (file size) and the built-in ls feature of find should be efficient, avoiding process creations or file i/o.

With zsh, you can use extended globbing to do:

du -c **/*.undo

find -name *.undo -print0 | du -hc --files0-from=-

du -c *pattern*

This will print the total on the last line of output.

I have been looking at this problem too (only a year later...) - only just found this page.

Something that I found works (for me) is the following:

find /mnt/iso -name *.avi -printf "%s\n" | paste -sd+ - | bc

This will return the total size of all the .avi files in all the sub-folders below /mnt/iso

I have to give credit to radoulov for the paste command - see this page: https://stackoverflow.com/questions/450799/linux-command-to-sum-integers-one-per-line

Just to add - just in case a folder matches the search term - it's a good idea to use -type f in the find command too.

find -name '*.undo' -exec wc -c {} + | tail -n 1

should give the actual total number of bytes in the files, if you don't have too many files (where "too many" is going to be a really large number, probably in the thousands). Or if you just want to get the number alone,

find -name '*.undo' -exec wc -c {} + | tail -n 1 | cut -d' ' -f 1

Python is part of most linux distributions.

import os
import fnmatch
size= 0
for path, dirs, files in os.walk( '.' ):
    for f in files:
        if fnmatch.fnmatch(f,'*.py'):
            fileSize= os.path.getsize( os.path.join(path,f) ) 
            print f, fileSize
            size += fileSize
print size

Longish, but perfectly clear and highly extensible.

find -name '*.undo' -print0 | du -hc --files0-from=- | tail -n 1

Put together from [gerdemb][1]'s and strager's contributions. Using du -cb should display bytes.

[1]: https://stackoverflow.com/users/27478/gerdemb "gerdemb"

I use du command like this to get the number only:

du file_list | awk '{s+=$1} END {print s}'

How about this simple one.

find ./ -name *.undo | xargs wc

Or, you can just do this:

dir=$1

for file in $dir/* ; do

 length_file=`stat -c %s $file`
 echo "File $file has length $length_file"
 length_total=`expr $length_total + $length_file`

done

echo "Total length: $length_total ."

Where stat displays a file or file system status. The argument -c means using the specified format instead of the default one, and the format sequence $s allows the display of the total size of bytes.

expr 

Just evaluates an expression.

Perl one-liner:

find . -name "*.undo" -ls | perl -lane '$t += $F[6]; END{print $t}'

The @F autosplit array starts at index $F[0] while awk fields start with $1, hence $F[6] is used instead of awk's $7

du -c | awk '/./{line=$0} END{print $1}'

I think the version with xargs could be imroved (simplified) ls -1 *.undo | xargs wc

Check the du (disk usage) command.