Bulk create model objects in django
DjangoDjango ModelsDjango Problem Overview
I have a lot of objects to save in database, and so I want to create Model instances with that.
With django, I can create all the models instances, with MyModel(data)
, and then I want to save them all.
Currently, I have something like that:
for item in items:
object = MyModel(name=item.name)
object.save()
I'm wondering if I can save a list of objects directly, eg:
objects = []
for item in items:
objects.append(MyModel(name=item.name))
objects.save_all()
How to save all the objects in one transaction?
Django Solutions
Solution 1 - Django
as of the django development, there exists bulk_create
as an object manager method which takes as input an array of objects created using the class constructor. check out django docs
Solution 2 - Django
Use bulk_create()
method. It's standard in Django now.
Example:
Entry.objects.bulk_create([
Entry(headline="Django 1.0 Released"),
Entry(headline="Django 1.1 Announced"),
Entry(headline="Breaking: Django is awesome")
])
Solution 3 - Django
worked for me to use manual transaction handling for the loop(postgres 9.1):
from django.db import transaction
with transaction.atomic():
for item in items:
MyModel.objects.create(name=item.name)
in fact it's not the same, as 'native' database bulk insert, but it allows you to avoid/descrease transport/orms operations/sql query analyse costs
Solution 4 - Django
Here is how to bulk-create entities from column-separated file, leaving aside all unquoting and un-escaping routines:
SomeModel(Model):
@classmethod
def from_file(model, file_obj, headers, delimiter):
model.objects.bulk_create([
model(**dict(zip(headers, line.split(delimiter))))
for line in file_obj],
batch_size=None)
Solution 5 - Django
name = request.data.get('name')
period = request.data.get('period')
email = request.data.get('email')
prefix = request.data.get('prefix')
bulk_number = int(request.data.get('bulk_number'))
bulk_list = list()
for _ in range(bulk_number):
code = code_prefix + uuid.uuid4().hex.upper()
bulk_list.append(
DjangoModel(name=name, code=code, period=period, user=email))
bulk_msj = DjangoModel.objects.bulk_create(bulk_list)
Solution 6 - Django
Using create will cause one query per new item. If you want to reduce the number of INSERT queries, you'll need to use something else.
I've had some success using the Bulk Insert snippet, even though the snippet is quite old. Perhaps there are some changes required to get it working again.
Solution 7 - Django
Check out this blog post on the bulkops module.
On my django 1.3 app, I have experienced significant speedup.
Solution 8 - Django
for a single line implementation, you can use a lambda expression in a map
map(lambda x:MyModel.objects.get_or_create(name=x), items)
Here, lambda matches each item in items list to x and create a Database record if necessary.
Solution 9 - Django
The easiest way is to use the create
Manager method, which creates and saves the object in a single step.
for item in items:
MyModel.objects.create(name=item.name)