Breaking out of nested loops
PythonLoopsNested LoopsPython Problem Overview
Is there an easier way to break out of nested loops than throwing an exception? (In Perl, you can give labels to each loop and at least continue an outer loop.)
for x in range(10):
for y in range(10):
print x*y
if x*y > 50:
"break both loops"
I.e., is there a nicer way than:
class BreakIt(Exception): pass
try:
for x in range(10):
for y in range(10):
print x*y
if x*y > 50:
raise BreakIt
except BreakIt:
pass
Python Solutions
Solution 1 - Python
for x in xrange(10):
for y in xrange(10):
print x*y
if x*y > 50:
break
else:
continue # only executed if the inner loop did NOT break
break # only executed if the inner loop DID break
The same works for deeper loops:
for x in xrange(10):
for y in xrange(10):
for z in xrange(10):
print x,y,z
if x*y*z == 30:
break
else:
continue
break
else:
continue
break
Solution 2 - Python
It has at least been suggested, but also rejected. I don't think there is another way, short of repeating the test or re-organizing the code. It is sometimes a bit annoying.
In the rejection message, Mr van Rossum mentions using return
, which is really sensible and something I need to remember personally. :)
Solution 3 - Python
If you're able to extract the loop code into a function, a return
statement can be used to exit the outermost loop at any time.
def foo():
for x in range(10):
for y in range(10):
print(x*y)
if x*y > 50:
return
foo()
If it's hard to extract that function you could use an inner function, as @bjd2385 suggests, e.g.
def your_outer_func():
...
def inner_func():
for x in range(10):
for y in range(10):
print(x*y)
if x*y > 50:
return
inner_func()
...
Solution 4 - Python
Use itertools.product!
from itertools import product
for x, y in product(range(10), range(10)):
#do whatever you want
break
Here's a link to itertools.product in the python documentation: http://docs.python.org/library/itertools.html#itertools.product
You can also loop over an array comprehension with 2 fors in it, and break whenever you want to.
>>> [(x, y) for y in ['y1', 'y2'] for x in ['x1', 'x2']]
[ ('x1', 'y1'), ('x2', 'y1'), ('x1', 'y2'), ('x2', 'y2')]
Solution 5 - Python
Sometimes I use a boolean variable. Naive, if you want, but I find it quite flexible and comfortable to read. Testing a variable may avoid testing again complex conditions and may also collect results from several tests in inner loops.
x_loop_must_break = False
for x in range(10):
for y in range(10):
print x*y
if x*y > 50:
x_loop_must_break = True
break
if x_loop_must_break: break
Solution 6 - Python
If you're going to raise an exception, you might raise a StopIteration exception. That will at least make the intent obvious.
Solution 7 - Python
You can also refactor your code to use a generator. But this may not be a solution for all types of nested loops.
Solution 8 - Python
In this particular case, you can merge the loops with a modern python (3.0 and probably 2.6, too) by using itertools.product.
I for myself took this as a rule of thumb, if you nest too many loops (as in, more than 2), you are usually able to extract one of the loops into a different method or merge the loops into one, as in this case.