C# binary literals

C# Problem Overview

Is there a way to write binary literals in C#, like prefixing hexadecimal with 0x? 0b doesn't work.

If not, what is an easy way to do it? Some kind of string conversion?

C# Solutions

Solution 1 - C#

###Update###

C# 7.0 now has binary literals, which is awesome.

[Flags]
enum Days
{
	None = 0,
	Sunday    = 0b0000001,
	Monday    = 0b0000010,   // 2
	Tuesday   = 0b0000100,   // 4
	Wednesday = 0b0001000,   // 8
	Thursday  = 0b0010000,   // 16
	Friday    = 0b0100000,   // etc.
	Saturday  = 0b1000000,
	Weekend = Saturday | Sunday,
	Weekdays = Monday | Tuesday | Wednesday | Thursday | Friday
}

###Original Post###

Since the topic seems to have turned to declaring bit-based flag values in enums, I thought it would be worth pointing out a handy trick for this sort of thing. The left-shift operator (<<) will allow you to push a bit to a specific binary position. Combine that with the ability to declare enum values in terms of other values in the same class, and you have a very easy-to-read declarative syntax for bit flag enums.

[Flags]
enum Days
{
    None        = 0,
    Sunday      = 1,
    Monday      = 1 << 1,   // 2
    Tuesday     = 1 << 2,   // 4
    Wednesday   = 1 << 3,   // 8
    Thursday    = 1 << 4,   // 16
    Friday      = 1 << 5,   // etc.
    Saturday    = 1 << 6,
    Weekend     = Saturday | Sunday,
    Weekdays    = Monday | Tuesday | Wednesday | Thursday | Friday
}

Solution 2 - C#

C# 7.0 supports binary literals (and optional digit separators via underscore characters).

An example:

int myValue = 0b0010_0110_0000_0011;

You can also find more information on the Roslyn GitHub page.

Solution 3 - C#

Only integer and hex directly, I'm afraid (ECMA 334v4):

> 9.4.4.2 Integer literals Integer literals are used to write values of > types int, uint, long, and ulong. > Integer literals have two possible > forms: decimal and hexadecimal.

To parse, you can use:

int i = Convert.ToInt32("01101101", 2);

Solution 4 - C#

Adding to @StriplingWarrior's answer about bit flags in enums, there's an easy convention you can use in hexadecimal for counting upwards through the bit shifts. Use the sequence 1-2-4-8, move one column to the left, and repeat.

[Flags]
enum Scenery
{
  Trees   = 0x001, // 000000000001
  Grass   = 0x002, // 000000000010
  Flowers = 0x004, // 000000000100
  Cactus  = 0x008, // 000000001000
  Birds   = 0x010, // 000000010000
  Bushes  = 0x020, // 000000100000
  Shrubs  = 0x040, // 000001000000
  Trails  = 0x080, // 000010000000
  Ferns   = 0x100, // 000100000000
  Rocks   = 0x200, // 001000000000
  Animals = 0x400, // 010000000000
  Moss    = 0x800, // 100000000000
}

Scan down starting with the right column and notice the pattern 1-2-4-8 (shift) 1-2-4-8 (shift) ...

To answer the original question, I second @Sahuagin's suggestion to use hexadecimal literals. If you're working with binary numbers often enough for this to be a concern, it's worth your while to get the hang of hexadecimal.

If you need to see binary numbers in source code, I suggest adding comments with binary literals like I have above.

Solution 5 - C#

You can always create quasi-literals, constants which contain the value you are after:

const int b001 = 1;
const int b010 = 2;
const int b011 = 3;
// etc ...
Debug.Assert((b001 | b010) == b011);

If you use them often then you can wrap them in a static class for re-use.

However, slightliy off-topic, if you have any semantics associated with the bits (known at compile time) I would suggest using an Enum instead:

enum Flags
{ 
    First = 0,
    Second = 1,
    Third = 2,
    SecondAndThird = 3
}
// later ...
Debug.Assert((Flags.Second | Flags.Third) == Flags.SecondAndThird);

Solution 6 - C#

If you look at the language feature implementation status of the .NET Compiler Platform ("Roslyn") you can clearly see that in C# 6.0 this is a planned feature, so in the next release we can do it in the usual way.

Binary literal status

Solution 7 - C#

string sTable="static class BinaryTable\r\n{";
string stemp = "";
for (int i = 0; i < 256; i++)
{
stemp = System.Convert.ToString(i, 2);
while(stemp.Length<8) stemp = "0" + stemp;
sTable += "\tconst char nb" + stemp + "=" + i.ToString() + ";\r\n";
}
sTable += "}";
Clipboard.Clear();
Clipboard.SetText ( sTable);
MessageBox.Show(sTable);

Using this, for 8bit binary, I use this to make a static class and it puts it into the clipboard.. Then it gets pasted into the project and added to the Using section, so anything with nb001010 is taken out of a table, at least static, but still... I use C# for a lot of PIC graphics coding and use 0b101010 a lot in Hi-Tech C

--sample from code outpt--

static class BinaryTable
{	const char nb00000000=0;
	const char nb00000001=1;
	const char nb00000010=2;
	const char nb00000011=3;
	const char nb00000100=4;
//etc, etc, etc, etc, etc, etc, etc, 
}

:-) NEAL

Solution 8 - C#

Binary literal feature was not implemented in C# 6.0 & Visual Studio 2015. but on 30-March 2016 Microsoft announced the new version of Visual Studio '15' Preview with that we can use binary literals.

We can use one or more than one Underscore( _ ) character for digit separators. so the code snippet would look something like:

int x           = 0b10___10_0__________________00; //binary value of 80
int SeventyFive = 0B100_________1011; //binary value of 75

WriteLine($" {x} \n {SeventyFive}");

and we can use either of 0b and 0B as shown in the above code snippet.

if you do not want to use digit separator you can use it without digit separator like below code snippet

int x           = 0b1010000; //binary value of 80
int SeventyFive = 0B1001011; //binary value of 75

WriteLine($" {x} \n {SeventyFive}");

Solution 9 - C#

While not possible using a Literal, maybe a BitConverter can also be a solution?

Solution 10 - C#

Though the string parsing solution is the most popular, I don't like it, because parsing string can be a great performance hit in some situations.

When there is needed a kind of a bitfield or binary mask, I'd rather write it like

> long bitMask = 1011001;

And later

> int bit5 = BitField.GetBit(bitMask, 5);

> bool flag5 = BitField.GetFlag(bitMask, 5);`

Where BitField class is

public static class BitField
{
    public static int GetBit(int bitField, int index)
    {
        return (bitField / (int)Math.Pow(10, index)) % 10;
    }

    public static bool GetFlag(int bitField, int index)
    {
        return GetBit(bitField, index) == 1;
    }
}

Solution 11 - C#

You can use 0b000001 since Visual Studio 2017 (C# 7.0)

Solution 12 - C#

Basically, I think the answer is NO, there is no easy way. Use decimal or hexadecimal constants - they are simple and clear. @RoyTinkers answer is also good - use a comment.

int someHexFlag = 0x010; // 000000010000
int someDecFlag = 8;     // 000000001000

The others answers here present several useful work-a rounds, but I think they aren't better then the simple answer. C# language designers probably considered a '0b' prefix unnecessary. HEX is easy to convert to binary, and most programmers are going to have to know the DEC equivalents of 0-8 anyways.

Also, when examining values in the debugger, they will be displayed has HEX or DEC.

Content Type	Original Author	Original Content on Stackoverflow
Question	toxvaerd	View Question on Stackoverflow
Solution 1 - C#	StriplingWarrior	View Answer on Stackoverflow
Solution 2 - C#	BTownTKD	View Answer on Stackoverflow
Solution 3 - C#	Marc Gravell	View Answer on Stackoverflow
Solution 4 - C#	Roy Tinker	View Answer on Stackoverflow
Solution 5 - C#	Markus Johnsson	View Answer on Stackoverflow
Solution 6 - C#	totymedli	View Answer on Stackoverflow
Solution 7 - C#	Neal	View Answer on Stackoverflow
Solution 8 - C#	Banketeshvar Narayan	View Answer on Stackoverflow
Solution 9 - C#	Michael Stum	View Answer on Stackoverflow
Solution 10 - C#	Dmitry Tashkinov	View Answer on Stackoverflow
Solution 11 - C#	Xiaoyuvax	View Answer on Stackoverflow
Solution 12 - C#	RaoulRubin	View Answer on Stackoverflow