Bash checking if string does not contain other string
BashBash Problem Overview
I have a string ${testmystring} in my .sh script and I want to check if this string does not contain another string.
if [[ ${testmystring} doesNotContain *"c0"* ]];then
# testmystring does not contain c0
fi
How can I do that, i.e. what is doesNotContain supposed to be?
Bash Solutions
Solution 1 - Bash
Use !=.
if [[ ${testmystring} != *"c0"* ]];then
# testmystring does not contain c0
fi
See help [[ for more information.
Solution 2 - Bash
Bash allow u to use =~ to test if the substring is contained. Ergo, the use of negate will allow to test the opposite.
fullstring="123asdf123"
substringA=asdf
substringB=gdsaf
# test for contains asdf, gdsaf and for NOT CONTAINS gdsaf
[[ $fullstring =~ $substring ]] && echo "found substring $substring in $fullstring"
[[ $fullstring =~ $substringB ]] && echo "found substring $substringB in $fullstring" || echo "failed to find"
[[ ! $fullstring =~ $substringB ]] && echo "did not find substring $substringB in $fullstring"
Solution 3 - Bash
As mainframer said, you can use grep, but i would use exit status for testing, try this:
#!/bin/bash
# Test if anotherstring is contained in teststring
teststring="put you string here"
anotherstring="string"
echo ${teststring} | grep --quiet "${anotherstring}"
# Exit status 0 means anotherstring was found
# Exit status 1 means anotherstring was not found
if [ $? = 1 ]
then
echo "$anotherstring was not found"
fi