Auto reloading python Flask app upon code changes

PythonApacheFlask

Python Problem Overview


I'm investigating how to develop a decent web app with Python. Since I don't want some high-order structures to get in my way, my choice fell on the lightweight Flask framework. Time will tell if this was the right choice.

So, now I've set up an Apache server with mod_wsgi, and my test site is running fine. However, I'd like to speed up the development routine by making the site automatically reload upon any changes in py or template files I make. I see that any changes in site's .wsgi file causes reloading (even without WSGIScriptReloading On in the apache config file), but I still have to prod it manually (ie, insert extra linebreak, save). Is there some way how to cause reload when I edit some of the app's py files? Or, I am expected to use IDE that refreshes the .wsgi file for me?

Python Solutions


Solution 1 - Python

The current recommended way is with the flask command line utility.

https://flask.palletsprojects.com/en/1.1.x/quickstart/#debug-mode

Example:

$ export FLASK_APP=main.py
$ export FLASK_ENV=development
$ flask run

or in one command:

$ FLASK_APP=main.py FLASK_ENV=development flask run

If you want different port than the default (5000) add --port option.

Example:

$ FLASK_APP=main.py FLASK_ENV=development flask run --port 8080

More options are available with:

$ flask run --help

FLASK_APP can also be set to module:app or module:create_app instead of module.py. See https://flask.palletsprojects.com/en/1.1.x/cli/#application-discovery for a full explanation.

Solution 2 - Python

If you are talking about test/dev environments, then just use the debug option. It will auto-reload the flask app when a code change happens.

app.run(debug=True)

Or, from the shell:

$ export FLASK_DEBUG=1
$ flask run

http://flask.pocoo.org/docs/quickstart/#debug-mode

Solution 3 - Python

In test/development environments

The werkzeug debugger already has an 'auto reload' function available that can be enabled by doing one of the following:

app.run(debug=True)

or

app.debug = True

You can also use a separate configuration file to manage all your setup if you need be. For example I use 'settings.py' with a 'DEBUG = True' option. Importing this file is easy too;

app.config.from_object('application.settings')

However this is not suitable for a production environment.

Production environment

Personally I chose Nginx + uWSGI over Apache + mod_wsgi for a few performance reasons but also the configuration options. The touch-reload option allows you to specify a file/folder that will cause the uWSGI application to reload your newly deployed flask app.

For example, your update script pulls your newest changes down and touches 'reload_me.txt' file. Your uWSGI ini script (which is kept up by Supervisord - obviously) has this line in it somewhere:

touch-reload = '/opt/virtual_environments/application/reload_me.txt'

I hope this helps!

Solution 4 - Python

If you're running using uwsgi look at the python auto reload option:

uwsgi --py-autoreload 1

Example uwsgi-dev-example.ini:

[uwsgi]
socket = 127.0.0.1:5000
master = true
virtualenv = /Users/xxxx/.virtualenvs/sites_env
chdir = /Users/xxx/site_root
module = site_module:register_debug_server()
callable = app
uid = myuser
chmod-socket = 660
log-date = true
workers = 1
py-autoreload = 1

site_root/_init_.py

def register_debug_server():
    from werkzeug.debug import DebuggedApplication

    app = Flask(__name__)
    app.debug = True
    app = DebuggedApplication(app, evalex=True)
    return app

Then run:

uwsgi --ini uwsgi-dev-example.ini

Note: This example also enables the debugger.

I went this route to mimic production as close as possible with my nginx setup. Simply running the flask app with it's built in web server behind nginx it would result in a bad gateway error.

Solution 5 - Python

A few updates for Flask 1.0 and above

the basic approach to hot re-loading is:

$ export FLASK_APP=my_application
$ export FLASK_ENV=development
$ flask run
  • you should use FLASK_ENV=development (not FLASK_DEBUG=1)

  • as a safety check, you can run flask run --debugger just to make sure it's turned on

  • the Flask CLI will now automatically read things like FLASK_APP and FLASK_ENV if you have an .env file in the project root and have python-dotenv installed

Solution 6 - Python

app.run(use_reloader=True)

we can use this, use_reloader so every time we reload the page our code changes will be updated.

Solution 7 - Python

Use this method:

app.run(debug=True)

It will auto-reload the flask app when a code change happens.

Sample code:

from flask import Flask

app = Flask(__name__)

@app.route("/")
def index():
   return "Hello World"


if __name__ == '__main__':
  app.run(debug=True)

Well, if you want save time not reloading the webpage everytime when changes happen, then you can try the keyboard shortcut Ctrl + R to reload the page quickly.

Solution 8 - Python

I got a different idea:

First:

pip install python-dotenv

Install the python-dotenv module, which will read local preference for your project environment.

Second:

Add .flaskenv file in your project directory. Add following code:

FLASK_ENV=development

It's done!

With this config for your Flask project, when you run flask run and you will see this output in your terminal:

enter image description here

And when you edit your file, just save the change. You will see auto-reload is there for you:

enter image description here

With more explanation:

Of course you can manually hit export FLASK_ENV=development every time you need. But using different configuration file to handle the actual working environment seems like a better solution, so I strongly recommend this method I use.

Solution 9 - Python

Flask applications can optionally be executed in debug mode. In this mode, two very convenient modules of the development server called the reloader and the debugger are enabled by default. When the reloader is enabled, Flask watches all the source code files of your project and automatically restarts the server when any of the files are modified.

By default, debug mode is disabled. To enable it, set a FLASK_DEBUG=1 environment variable before invoking flask run:

(venv) $ export FLASK_APP=hello.py for Windows use > set FLASK_APP=hello.py

(venv) $ export FLASK_DEBUG=1 for Windows use > set FLASK_DEBUG=1

(venv) $ flask run

* Serving Flask app "hello"
* Forcing debug mode on
* Running on http://127.0.0.1:5000/ (Press CTRL+C to quit)
* Restarting with stat
* Debugger is active!
* Debugger PIN: 273-181-528

Having a server running with the reloader enabled is extremely useful during development, because every time you modify and save a source file, the server automatically restarts and picks up the change.

Solution 10 - Python

From the terminal you can simply say

export FLASK_APP=app_name.py
export FLASK_ENV=development
flask run

or in your file

if __name__ == "__main__":
    app.run(debug=True)

Solution 11 - Python

To achieve this in PyCharm set 'Environment Variables' section to:

PYTHONUNBUFFERED=1;
FLASK_DEBUG=1

For Flask 'run / debug configurations'.

Solution 12 - Python

To help with fast automatic change in browser:

pip install livereload

from livereload import Server

if __name__ == '__main__':
    server = Server(app.wsgi_app)
    server.serve()

Next, Start your server again:

eg. your .py file is app.py

python app.py

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