Array.include? multiple values

Ruby

Ruby Problem Overview


[2, 6, 13, 99, 27].include?(2) works well for checking if the array includes one value. But what if I want to check if an array includes any one from a list of multiple values? Is there a shorter way than doing Array.include?(a) or Array.include?(b) or Array.include?(c) ...?

Ruby Solutions


Solution 1 - Ruby

You could take the intersection of two arrays, and see if it's not empty:

([2, 6, 13, 99, 27] & [2, 6]).any?

Solution 2 - Ruby

You can use the Enumerable#any? method with a code block to test for inclusion of multiple values. For example, to check for either 6 or 13:

[2, 6, 13, 99, 27].any? { |i| [6, 13].include? i }

Solution 3 - Ruby

I was interested in seeing how these various approach compared in performance, not so much for the problem at hand, but more for general comparisons of array vs set intersection, array vs set include? and include? vs index for arrays. I will edit to add other methods that are suggested, and let me know if you'd like to see different benchmark parameters.

I for one would like to see more benchmarking of SO answers done. It's not difficult or time-consuming, and it can provide useful insights. I find most of the time is preparing the test cases. Notice I've put the methods to be tested in a module, so if another method is to be benchmarked, I need only add that method to the module.

Methods compared

module Methods
  require 'set'
  def august(a,b)    (a&b).any? end
  def gnome_inc(a,b) a.any? { |i| b.include? i } end
  def gnome_ndx(a,b) a.any? { |i| b.index i } end
  def gnome_set(a,b) bs=b.to_set; a.any? { |i| bs.include? i } end
  def vii_stud(a,b)  as, bs = Set.new(a), Set.new(b); as.intersect?(bs) end
end

include Methods
@methods = Methods.instance_methods(false)
  #=> [:august, :gnome_inc, :gnome_ndx, :gnome_set, :vii_stud]

Test data

def test_data(n,m,c,r)
  # n: nbr of elements in a
  # m: nbr of elements in b
  # c: nbr of elements common to a & b
  # r: repetitions
  r.times.each_with_object([]) { |_,a|
    a << [n.times.to_a.shuffle, [*(n-c..n-c-1+m)].shuffle] }
end

d = test_data(10,4,2,2)
  #=> [[[7, 8, 0, 3, 2, 9, 1, 6, 5, 4], [11, 10,  9, 8]], 
  #    [[2, 6, 3, 4, 7, 8, 0, 9, 1, 5], [ 9, 11, 10, 8]]]
# Before `shuffle`, each of the two elements is:
  #=> [[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [8, 9, 10, 11]] 

def compute(d, m)
  d.each_with_object([]) { |(a,b),arr| arr << send(m, a, b) }
end  

compute(d, :august)
 #=> [true, true]

Confirm methods return the same values

d = test_data(1000,100,10,3)
r0 = compute(d, @methods.first) 
puts @methods[1..-1].all? { |m| r0 == compute(d, m) }
  #=> true

Benchmark code

require 'benchmark'

@indent = methods.map { |m| m.to_s.size }.max

def test(n, m, c, r, msg)
  puts "\n#{msg}"
  puts "n = #{n}, m = #{m}, overlap = #{c}, reps = #{r}"
  d = test_data(n, m, c, r)
  Benchmark.bm(@indent) do |bm|
    @methods.each do |m|
      bm.report m.to_s do
        compute(d, m)
      end
    end
  end
end

Tests

n = 100_000
m = 1000
test(n, m,    0,  1, "Zero overlap")
test(n, m, 1000,  1, "Complete overlap")
test(n, m,    1, 20, "Overlap of 1")
test(n, m,    5, 20, "Overlap of 5")
test(n, m,   10, 20, "Overlap of 10")
test(n, m,   20, 20, "Overlap of 20")
test(n, m,   50, 20, "Overlap of 50")
test(n, m,  100, 20, "Overlap of 100")


Zero overlap n = 100000, m = 1000, overlap = 0, reps = 1 user system total real august 0.010000 0.000000 0.010000 ( 0.005491) gnome_inc 4.480000 0.010000 4.490000 ( 4.500531) gnome_ndx 0.810000 0.000000 0.810000 ( 0.822412) gnome_set 0.030000 0.000000 0.030000 ( 0.031668) vii_stud 0.080000 0.010000 0.090000 ( 0.084283)


Complete overlap n = 100000, m = 1000, overlap = 1000, reps = 1 user system total real august 0.000000 0.000000 0.000000 ( 0.005841) gnome_inc 0.010000 0.000000 0.010000 ( 0.002521) gnome_ndx 0.000000 0.000000 0.000000 ( 0.000350) gnome_set 0.000000 0.000000 0.000000 ( 0.000655) vii_stud 0.090000 0.000000 0.090000 ( 0.097850)


Overlap of 1 n = 100000, m = 1000, overlap = 1, reps = 20 user system total real august 0.110000 0.000000 0.110000 ( 0.116276) gnome_inc 61.790000 0.100000 61.890000 ( 62.058320) gnome_ndx 10.100000 0.020000 10.120000 ( 10.144649) gnome_set 0.360000 0.000000 0.360000 ( 0.357878) vii_stud 1.450000 0.050000 1.500000 ( 1.501705)


Overlap of 5 n = 100000, m = 1000, overlap = 5, reps = 20 user system total real august 0.110000 0.000000 0.110000 ( 0.113747) gnome_inc 16.550000 0.050000 16.600000 ( 16.728505) gnome_ndx 2.470000 0.000000 2.470000 ( 2.475111) gnome_set 0.100000 0.000000 0.100000 ( 0.099874) vii_stud 1.630000 0.060000 1.690000 ( 1.703650)


Overlap of 10 n = 100000, m = 1000, overlap = 10, reps = 20 user system total real august 0.110000 0.000000 0.110000 ( 0.112674) gnome_inc 10.090000 0.020000 10.110000 ( 10.131339) gnome_ndx 1.470000 0.000000 1.470000 ( 1.478400) gnome_set 0.060000 0.000000 0.060000 ( 0.062762) vii_stud 1.430000 0.050000 1.480000 ( 1.476961)


Overlap of 20 n = 100000, m = 1000, overlap = 20, reps = 20 user system total real august 0.100000 0.000000 0.100000 ( 0.108350) gnome_inc 4.020000 0.000000 4.020000 ( 4.026290) gnome_ndx 0.660000 0.010000 0.670000 ( 0.663001) gnome_set 0.030000 0.000000 0.030000 ( 0.024606) vii_stud 1.380000 0.050000 1.430000 ( 1.437340)


Overlap of 50 n = 100000, m = 1000, overlap = 50, reps = 20 user system total real august 0.120000 0.000000 0.120000 ( 0.121278) gnome_inc 2.170000 0.000000 2.170000 ( 2.236737) gnome_ndx 0.310000 0.000000 0.310000 ( 0.308336) gnome_set 0.020000 0.000000 0.020000 ( 0.015326) vii_stud 1.220000 0.040000 1.260000 ( 1.259828)


Overlap of 100 n = 100000, m = 1000, overlap = 100, reps = 20 user system total real august 0.110000 0.000000 0.110000 ( 0.112739) gnome_inc 0.720000 0.000000 0.720000 ( 0.712265) gnome_ndx 0.100000 0.000000 0.100000 ( 0.105420) gnome_set 0.010000 0.000000 0.010000 ( 0.009398) vii_stud 1.400000 0.050000 1.450000 ( 1.447110)

Solution 4 - Ruby

Simple way:

([2, 6] - [2, 6, 13, 99, 27]).empty?

Solution 5 - Ruby

One of my favourite methods of doing that in specs is to convert an array and a value to the Set and check it via #superset? & #subset? methods.

For example:

[1, 2, 3, 4, 5].to_set.superset?([1, 2, 3].to_set) # true
[1, 2, 3].to_set.subset?([1, 2, 3, 4, 5].to_set)   # true
[1, 2].to_set.subset?([1, 2].to_set)               # true
[1, 2].to_set.superset?([1, 2].to_set)             # true

However, being a set means that all values in a collection are unique, so it may not always be appropriate:

[1, 1, 1, 1, 1].to_set.subset? [1, 2].to_set       # true

To avoid calling .to_set every time I usually define a matcher for that:

it 'returns array of "shown" proposals' do
  expect(body_parsed.first.keys).to be_subset_of(hidden_prop_attrs)
end

In my humble opinion, being a superset or a subset is just more readable than doing:

([1, 2, 3] & [1, 2]).any?

However, converting an array to a set may be a less performant. Tradeoffs ¯\(ツ)

Solution 6 - Ruby

If you want to check two elements are present in the array.

2.4.1 :221 >   ([2, 6, 13, 99, 27] & [2, 6]).many?
 => true

Solution 7 - Ruby

require 'set'

master = Set.new [2, 6, 13, 99, 27]
data = Set.new [27, -3, -4]
#puts data.subset?(master) ? 'yes' : 'no'  #per @meager comment
puts data.intersect?(master) ? 'yes' : 'no'

--output:--
yes

Solution 8 - Ruby

I extend Array with these:

class Array

  def include_exactly?(values)
    self.include_all?(values) && (self.length == values.length)
  end
  def include_any?(values)
    values.any? {|value| self.include?(value)}
  end
  def include_all?(values)
    values.all? {|value| self.include?(value)}
  end
  def exclude_all?(values)
    values.all? {|value| self.exclude?(value)}
  end

end

Solution 9 - Ruby

This works - if any of the value matches:

arr = [2, 6, 13, 99, 27]
if (arr - [2, 6]).size < arr.size
 puts 'element match found'
else
 puts 'element not found'
end

Solution 10 - Ruby

Better solution :

class Array

  def include_any?(arr)
    (self & Array(arr)).any?
  end

end

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionAaron HooperView Question on Stackoverflow
Solution 1 - RubyAugustView Answer on Stackoverflow
Solution 2 - RubyTodd A. JacobsView Answer on Stackoverflow
Solution 3 - RubyCary SwovelandView Answer on Stackoverflow
Solution 4 - RubyNaveen KumarView Answer on Stackoverflow
Solution 5 - RubyDanny OceanView Answer on Stackoverflow
Solution 6 - RubyDyaniyal WilsonView Answer on Stackoverflow
Solution 7 - Ruby7studView Answer on Stackoverflow
Solution 8 - RubyYarinView Answer on Stackoverflow
Solution 9 - RubyLaluView Answer on Stackoverflow
Solution 10 - RubyMatrixView Answer on Stackoverflow