Applying function with multiple arguments to create a new pandas column
PythonPandasPython Problem Overview
I want to create a new column in a pandas
data frame by applying a function to two existing columns. Following this answer I've been able to create a new column when I only need one column as an argument:
import pandas as pd
df = pd.DataFrame({"A": [10,20,30], "B": [20, 30, 10]})
def fx(x):
return x * x
print(df)
df['newcolumn'] = df.A.apply(fx)
print(df)
However, I cannot figure out how to do the same thing when the function requires multiple arguments. For example, how do I create a new column by passing column A and column B to the function below?
def fxy(x, y):
return x * y
Python Solutions
Solution 1 - Python
You can go with @greenAfrican example, if it's possible for you to rewrite your function. But if you don't want to rewrite your function, you can wrap it into anonymous function inside apply, like this:
>>> def fxy(x, y):
... return x * y
>>> df['newcolumn'] = df.apply(lambda x: fxy(x['A'], x['B']), axis=1)
>>> df
A B newcolumn
0 10 20 200
1 20 30 600
2 30 10 300
Solution 2 - Python
Alternatively, you can use numpy underlying function:
>>> import numpy as np
>>> df = pd.DataFrame({"A": [10,20,30], "B": [20, 30, 10]})
>>> df['new_column'] = np.multiply(df['A'], df['B'])
>>> df
A B new_column
0 10 20 200
1 20 30 600
2 30 10 300
or vectorize arbitrary function in general case:
>>> def fx(x, y):
... return x*y
...
>>> df['new_column'] = np.vectorize(fx)(df['A'], df['B'])
>>> df
A B new_column
0 10 20 200
1 20 30 600
2 30 10 300
Solution 3 - Python
This solves the problem:
df['newcolumn'] = df.A * df.B
You could also do:
def fab(row):
return row['A'] * row['B']
df['newcolumn'] = df.apply(fab, axis=1)
Solution 4 - Python
If you need to create multiple columns at once:
-
Create the dataframe:
import pandas as pd df = pd.DataFrame({"A": [10,20,30], "B": [20, 30, 10]})
-
Create the function:
def fab(row): return row['A'] * row['B'], row['A'] + row['B']
-
Assign the new columns:
df['newcolumn'], df['newcolumn2'] = zip(*df.apply(fab, axis=1))
Solution 5 - Python
One more dict style clean syntax:
df["new_column"] = df.apply(lambda x: x["A"] * x["B"], axis = 1)
or,
df["new_column"] = df["A"] * df["B"]
Solution 6 - Python
This will dynamically give you desired result. It works even if you have more than two arguments
df['anothercolumn'] = df[['A', 'B']].apply(lambda x: fxy(*x), axis=1)
print(df)
A B newcolumn anothercolumn
0 10 20 100 200
1 20 30 400 600
2 30 10 900 300