Appending to an ObjectOutputStream

JavaSerializationAppendObjectoutputstreamObjectinputstream

Java Problem Overview


Is it not possible to append to an ObjectOutputStream?

I am trying to append to a list of objects. Following snippet is a function that is called whenever a job is finished.

FileOutputStream fos = new FileOutputStream
	       (preferences.getAppDataLocation() + "history" , true);
ObjectOutputStream out = new ObjectOutputStream(fos);

out.writeObject( new Stuff(stuff) );
out.close();

But when I try to read it I only get the first in the file. Then I get java.io.StreamCorruptedException.

To read I am using

FileInputStream fis = new FileInputStream
		( preferences.getAppDataLocation() + "history");
ObjectInputStream in = new ObjectInputStream(fis);    

try{
    while(true)
        history.add((Stuff) in.readObject());
}catch( Exception e ) { 
    System.out.println( e.toString() );
}

I do not know how many objects will be present so I am reading while there are no exceptions. From what Google says this is not possible. I was wondering if anyone knows a way?

Java Solutions


Solution 1 - Java

Here's the trick: subclass ObjectOutputStream and override the writeStreamHeader method:

public class AppendingObjectOutputStream extends ObjectOutputStream {

  public AppendingObjectOutputStream(OutputStream out) throws IOException {
    super(out);
  }

  @Override
  protected void writeStreamHeader() throws IOException {
    // do not write a header, but reset:
    // this line added after another question
    // showed a problem with the original
    reset();
  }

}

To use it, just check whether the history file exists or not and instantiate either this appendable stream (in case the file exists = we append = we don't want a header) or the original stream (in case the file does not exist = we need a header).

Edit

I wasn't happy with the first naming of the class. This one's better: it describes the 'what it's for' rather then the 'how it's done'

Edit

Changed the name once more, to clarify, that this stream is only for appending to an existing file. It can't be used to create a new file with object data.

Edit

Added a call to reset() after https://stackoverflow.com/questions/12279245/classcastexception-when-appending-object-outputstream/12438141#12438141">this question showed that the original version that just overrode writeStreamHeader to be a no-op could under some conditions create a stream that couldn't be read.

Solution 2 - Java

As the API says, the ObjectOutputStream constructor writes the serialization stream header to the underlying stream. And this header is expected to be only once, in the beginning of the file. So calling

new ObjectOutputStream(fos);

multiple times on the FileOutputStream that refers to the same file will write the header multiple times and corrupt the file.

Solution 3 - Java

Because of the precise format of the serialized file, appending will indeed corrupt it. You have to write all objects to the file as part of the same stream, or else it will crash when it reads the stream metadata when it's expecting an object.

You could read the Serialization Specification for more details, or (easier) read this thread where Roedy Green says basically what I just said.

Solution 4 - Java

The easiest way to avoid this problem is to keep the OutputStream open when you write the data, instead of closing it after each object. Calling reset() might be advisable to avoid a memory leak.

The alternative would be to read the file as a series of consecutive ObjectInputStreams as well. But this requires you to keep count how many bytes you read (this can be implementd with a FilterInputStream), then close the InputStream, open it again, skip that many bytes and only then wrap it in an ObjectInputStream().

Solution 5 - Java

I have extended the accepted solution to create a class that can be used for both appending and creating new file.

import java.io.DataOutputStream;
import java.io.IOException;
import java.io.ObjectOutputStream;
import java.io.OutputStream;

public class AppendableObjectOutputStream extends ObjectOutputStream {

	private boolean append;
	private boolean initialized;
	private DataOutputStream dout;
	
	protected AppendableObjectOutputStream(boolean append) throws IOException, SecurityException {
		super();
		this.append = append;
		this.initialized = true;
	}
	
	public AppendableObjectOutputStream(OutputStream out, boolean append) throws IOException {
		super(out);
		this.append = append;
		this.initialized = true;
		this.dout = new DataOutputStream(out);
		this.writeStreamHeader();
	}

	@Override
	protected void writeStreamHeader() throws IOException {
		if (!this.initialized || this.append) return;
		if (dout != null) {
			dout.writeShort(STREAM_MAGIC);
			dout.writeShort(STREAM_VERSION);
		}
	}
	
}

This class can be used as a direct extended replacement for ObjectOutputStream. We can use the class as follows:

import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;

public class ObjectWriter {

	public static void main(String[] args) {
		
		File file = new File("file.dat");
		boolean append = file.exists(); // if file exists then append, otherwise create new
		
		try (
			FileOutputStream fout = new FileOutputStream(file, append);
			AppendableObjectOutputStream oout = new AppendableObjectOutputStream(fout, append);
		) {
			oout.writeObject(...); // replace "..." with serializable object to be written
		} catch (FileNotFoundException e) {
			e.printStackTrace();
		} catch (IOException e) {
			e.printStackTrace();
		}
		
	}
	
}

Solution 6 - Java

How about before each time you append an object, read and copying all the current data in the file and then overwrite all together to file.

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionHamza YerlikayaView Question on Stackoverflow
Solution 1 - JavaAndreas DolkView Answer on Stackoverflow
Solution 2 - JavaTadeusz Kopec for UkraineView Answer on Stackoverflow
Solution 3 - JavaMichael MyersView Answer on Stackoverflow
Solution 4 - JavaMichael BorgwardtView Answer on Stackoverflow
Solution 5 - JavaPratanu MandalView Answer on Stackoverflow
Solution 6 - Javauser4147874View Answer on Stackoverflow