angular 2 how to return data from subscribe

JavascriptAngularTypescriptAsynchronous

Javascript Problem Overview


This is What I Want To Do.

@Component({
   selector: "data",
   template: "<h1>{{ getData() }}</h1>"
})

export class DataComponent{
    this.http.get(path).subscribe({
       res => return res;
    })
}

If getData was called inside the DataComponent, You may suggest assign it to a variable like this.data = res and use i like {{data}}.But I needed to use like {{getData}} for my own purpose.Please suggest me?

Javascript Solutions


Solution 1 - Javascript

You just can't return the value directly because it is an async call. An async call means it is running in the background (actually scheduled for later execution) while your code continues to execute.

You also can't have such code in the class directly. It needs to be moved into a method or the constructor.

What you can do is not to subscribe() directly but use an operator like map()

export class DataComponent{
    someMethod() {
      return this.http.get(path).map(res => {
        return res.json();
      });
    }
}

In addition, you can combine multiple .map with the same Observables as sometimes this improves code clarity and keeps things separate. Example:

validateResponse = (response) => validate(response);

parseJson = (json) => JSON.parse(json);

fetchUnits() {
    return this.http.get(requestUrl).map(this.validateResponse).map(this.parseJson);
}

This way an observable will be return the caller can subscribe to

export class DataComponent{
    someMethod() {
      return this.http.get(path).map(res => {
        return res.json();
      });
    }

    otherMethod() {
      this.someMethod().subscribe(data => this.data = data);
    }
}

The caller can also be in another class. Here it's just for brevity.

data => this.data = data

and

res => return res.json()

are arrow functions. They are similar to normal functions. These functions are passed to subscribe(...) or map(...) to be called from the observable when data arrives from the response. This is why data can't be returned directly, because when someMethod() is completed, the data wasn't received yet.

Solution 2 - Javascript

Two ways I know of:

export class SomeComponent implements OnInit
{
    public localVar:any;

    ngOnInit(){
        this.http.get(Path).map(res => res.json()).subscribe(res => this.localVar = res);
    }
}

This will assign your result into local variable once information is returned just like in a promise. Then you just do {{ localVar }}

Another Way is to get a observable as a localVariable.

export class SomeComponent
{
    public localVar:any;
 
    constructor()
    {
        this.localVar = this.http.get(path).map(res => res.json());
    }
}

This way you're exposing a observable at which point you can do in your html is to use AsyncPipe {{ localVar | async }}

Please try it out and let me know if it works. Also, since angular 2 is pretty new, feel free to comment if something is wrong.

Hope it helps

Solution 3 - Javascript

How about storing this one in a variable that can be used outside subscribe?

this.bindPlusService.getJSONCurrentRequestData(submission).map(data => {
	return delete JSON.parse(data)['$id'];
});

Solution 4 - Javascript

I have used this way lots time ...

@Component({
   selector: "data",
   template: "<h1>{{ getData() }}</h1>"
})

export class DataComponent{
    this.http.get(path).subscribe({
       DataComponent.setSubscribeData(res);
    })
}


static subscribeData:any;
static setSubscribeData(data):any{
    DataComponent.subscribeData=data;
    return data;
}

use static keyword and save your time... here either you can use static variable or directly return object you want.... hope it will help you.. happy coding...

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questiontsadkan yitbarekView Question on Stackoverflow
Solution 1 - JavascriptGünter ZöchbauerView Answer on Stackoverflow
Solution 2 - Javascriptqwerty_igorView Answer on Stackoverflow
Solution 3 - JavascriptJuliusView Answer on Stackoverflow
Solution 4 - Javascriptsajal rajabhojView Answer on Stackoverflow