Android Room @Delete with parameters

I know I can't use DELETE in a query (that is a shame by the way), I will get the following error:

<i>Error:error: Observable query return type (LiveData, Flowable etc) can only be used with SELECT queries that directly or indirectly (via @Relation, for example) access at least one table.</i>

But I can't use @Delete(WHERE... xxx) So how do I delete a specific row by a parameter?

Actually, you can use @Query to perform a delete.

@Query("DELETE FROM users WHERE user_id = :userId")
abstract void deleteByUserId(long userId);

Extracted from Query javadoc:

> UPDATE or DELETE queries can return void or int. If it is an int, the > value is the number of rows affected by this query.

The beauty of room is, we play with the objects. As per requirement you can use for kotlin:

@Delete
fun delete(model: LanguageModel)

for Java:

@Delete
void delete(LanguageModel model)

it will delete the exact object which is stored in the db with the same values. LanguageModel is my model class and it works perfectly.

You can use below method to delete by ID

@Query("DELETE FROM yourDatabaseTable WHERE id = :id")
void deleteById(int id);

for delete all rows

@Query("DELETE FROM yourDatabaseTable")
void delete();

ROOM database provides easy way to INSERT, UPDATE and DELETE an object in the database. To perform thus operation just needed to annotate @Delete. The DELETE operation returns the Int when deletion of the single object is successful returns 1 else returns 0 if the DELETE operation is unsuccessful, Adding the return type is a good practice.

KotlinEG.kt

   @Dao
   interface EntityLocalDAO {
       @Delete
       fun deleteData(entityObject: EntityObject) : Int
   }

javaEG.java

   @Dao
   interface EntityLocalDAO {
       @Delete
       int deleteData(EntityObject entityObject);
   }