Android HttpPost: how to get the result
JavaAndroidHttpJava Problem Overview
I have been trying long to send an HttpPost request and retrieve response but even though I was able to make a connection I don't yet get how to get the string message which is returned by the request-response
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.myurl.com/app/page.php");
// Add your data
List < NameValuePair > nameValuePairs = new ArrayList < NameValuePair > (5);
nameValuePairs.add(new BasicNameValuePair("type", "20"));
nameValuePairs.add(new BasicNameValuePair("mob", "919895865899"));
nameValuePairs.add(new BasicNameValuePair("pack", "0"));
nameValuePairs.add(new BasicNameValuePair("exchk", "1"));
try {
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
Log.d("myapp", "works till here. 2");
try {
HttpResponse response = httpclient.execute(httppost);
Log.d("myapp", "response " + response.getEntity());
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
I'm sorry, I sound very naive because I'm new to java. Please help me.
Java Solutions
Solution 1 - Java
Try to use the EntityUtil on your response:
String responseBody = EntityUtils.toString(response.getEntity());
Solution 2 - Java
URL url;
url = new URL("http://www.url.com/app.php");
URLConnection connection;
connection = url.openConnection();
HttpURLConnection httppost = (HttpURLConnection) connection;
httppost.setDoInput(true);
httppost.setDoOutput(true);
httppost.setRequestMethod("POST");
httppost.setRequestProperty("User-Agent", "Tranz-Version-t1.914");
httppost.setRequestProperty("Accept_Language", "en-US");
httppost.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
DataOutputStream dos = new DataOutputStream(httppost.getOutputStream());
dos.write(b); // bytes[] b of post data
String reply;
InputStream in = httppost.getInputStream();
StringBuffer sb = new StringBuffer();
try {
int chr;
while ((chr = in.read()) != -1) {
sb.append((char) chr);
}
reply = sb.toString();
} finally {
in.close();
}
This code snippet works. I got it after along search , but from a J2ME code.
Solution 3 - Java
You can call execute method with a ResponseHandler. Here's an example:
ResponseHandler<String> responseHandler = new BasicResponseHandler();
String response = httpClient.execute(httppost, responseHandler);
Solution 4 - Java
You can do this by this way :
public class MyHttpPostProjectActivity extends Activity implements OnClickListener {
private EditText usernameEditText;
private EditText passwordEditText;
private Button sendPostReqButton;
private Button clearButton;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.login);
usernameEditText = (EditText) findViewById(R.id.login_username_editText);
passwordEditText = (EditText) findViewById(R.id.login_password_editText);
sendPostReqButton = (Button) findViewById(R.id.login_sendPostReq_button);
sendPostReqButton.setOnClickListener(this);
clearButton = (Button) findViewById(R.id.login_clear_button);
clearButton.setOnClickListener(this);
}
@Override
public void onClick(View v) {
if(v.getId() == R.id.login_clear_button){
usernameEditText.setText("");
passwordEditText.setText("");
passwordEditText.setCursorVisible(false);
passwordEditText.setFocusable(false);
usernameEditText.setCursorVisible(true);
passwordEditText.setFocusable(true);
}else if(v.getId() == R.id.login_sendPostReq_button){
String givenUsername = usernameEditText.getEditableText().toString();
String givenPassword = passwordEditText.getEditableText().toString();
System.out.println("Given username :" + givenUsername + " Given password :" + givenPassword);
sendPostRequest(givenUsername, givenPassword);
}
}
private void sendPostRequest(String givenUsername, String givenPassword) {
class SendPostReqAsyncTask extends AsyncTask<String, Void, String>{
@Override
protected String doInBackground(String... params) {
String paramUsername = params[0];
String paramPassword = params[1];
System.out.println("*** doInBackground ** paramUsername " + paramUsername + " paramPassword :" + paramPassword);
HttpClient httpClient = new DefaultHttpClient();
// In a POST request, we don't pass the values in the URL.
//Therefore we use only the web page URL as the parameter of the HttpPost argument
HttpPost httpPost = new HttpPost("http://www.nirmana.lk/hec/android/postLogin.php");
// Because we are not passing values over the URL, we should have a mechanism to pass the values that can be
//uniquely separate by the other end.
//To achieve that we use BasicNameValuePair
//Things we need to pass with the POST request
BasicNameValuePair usernameBasicNameValuePair = new BasicNameValuePair("paramUsername", paramUsername);
BasicNameValuePair passwordBasicNameValuePAir = new BasicNameValuePair("paramPassword", paramPassword);
// We add the content that we want to pass with the POST request to as name-value pairs
//Now we put those sending details to an ArrayList with type safe of NameValuePair
List<NameValuePair> nameValuePairList = new ArrayList<NameValuePair>();
nameValuePairList.add(usernameBasicNameValuePair);
nameValuePairList.add(passwordBasicNameValuePAir);
try {
// UrlEncodedFormEntity is an entity composed of a list of url-encoded pairs.
//This is typically useful while sending an HTTP POST request.
UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(nameValuePairList);
// setEntity() hands the entity (here it is urlEncodedFormEntity) to the request.
httpPost.setEntity(urlEncodedFormEntity);
try {
// HttpResponse is an interface just like HttpPost.
//Therefore we can't initialize them
HttpResponse httpResponse = httpClient.execute(httpPost);
// According to the JAVA API, InputStream constructor do nothing.
//So we can't initialize InputStream although it is not an interface
InputStream inputStream = httpResponse.getEntity().getContent();
InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
StringBuilder stringBuilder = new StringBuilder();
String bufferedStrChunk = null;
while((bufferedStrChunk = bufferedReader.readLine()) != null){
stringBuilder.append(bufferedStrChunk);
}
return stringBuilder.toString();
} catch (ClientProtocolException cpe) {
System.out.println("First Exception caz of HttpResponese :" + cpe);
cpe.printStackTrace();
} catch (IOException ioe) {
System.out.println("Second Exception caz of HttpResponse :" + ioe);
ioe.printStackTrace();
}
} catch (UnsupportedEncodingException uee) {
System.out.println("An Exception given because of UrlEncodedFormEntity argument :" + uee);
uee.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
if(result.equals("working")){
Toast.makeText(getApplicationContext(), "HTTP POST is working...", Toast.LENGTH_LONG).show();
}else{
Toast.makeText(getApplicationContext(), "Invalid POST req...", Toast.LENGTH_LONG).show();
}
}
}
SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
sendPostReqAsyncTask.execute(givenUsername, givenPassword);
}
}
Solution 5 - Java
Try this, it seems to be the most compact. Although in the real world, you'd need to use an asynchronous request so the device won't hang while the requested page is being retrieved.
http://www.softwarepassion.com/android-series-get-post-and-multipart-post-requests/
Solution 6 - Java
You should try using HttpGet instead of HttpPost. I had a similar problem and that solved it.