Android: How do I get string from resources using its name?

AndroidStringResources

Android Problem Overview


I would like to have 2 languages for the UI and separate string values for them in my resource file res\values\strings.xml:

<string name="tab_Books_en">Books</string>
<string name="tab_Quotes_en">Quotes</string>
<string name="tab_Questions_en">Questions</string>
<string name="tab_Notes_en">Notes</string>
<string name="tab_Bookmarks_en">Bookmarks</string>

<string name="tab_Books_ru">Книги</string>
<string name="tab_Quotes_ru">Цитаты</string>
<string name="tab_Questions_ru">Вопросы</string>
<string name="tab_Notes_ru">Заметки</string>
<string name="tab_Bookmarks_ru">Закладки</string>

Now I need to retrieve these values dynamically in my app:

spec.setContent(R.id.tabPage1);
String pack = getPackageName();
String id = "tab_Books_" + Central.lang;
int i = Central.Res.getIdentifier(id, "string", pack);
String str = Central.Res.getString(i);

My problem is that i = 0.

Why does not it work in my case?

Android Solutions


Solution 1 - Android

The link you are referring to seems to work with strings generated at runtime. The strings from strings.xml are not created at runtime. You can get them via

String mystring = getResources().getString(R.string.mystring);

getResources() is a method of the Context class. If you are inside a Activity or a Service (which extend Context) you can use it like in this snippet.

Also note that the whole language dependency can be taken care of by the android framework. Simply create different folders for each language. If english is your default language, just put the english strings into res/values/strings.xml. Then create a new folder values-ru and put the russian strings with identical names into res/values-ru/strings.xml. From this point on android selects the correct one depending on the device locale for you, either when you call getString() or when referencing strings in XML via @string/mystring. The ones from res/values/strings.xml are the fallback ones, if you don't have a folder covering the users locale, this one will be used as default values.

See Localization and Providing Resources for more information.

Solution 2 - Android

Verify if your packageName is correct. You have to refer for the root package of your Android application.

private String getStringResourceByName(String aString) {
	  String packageName = getPackageName();
	  int resId = getResources().getIdentifier(aString, "string", packageName);
	  return getString(resId);
	}

Solution 3 - Android

Not from activities only:

public static String getStringByIdName(Context context, String idName) {
    Resources res = context.getResources();
    return res.getString(res.getIdentifier(idName, "string", context.getPackageName()));
}

Solution 4 - Android

getResources().getString(getResources().getIdentifier("propertyName", "string", getPackageName()))

Solution 5 - Android

I would add something to the solution of leonvian, so if by any chance the string is not found among the resources (return value 0, that is not a valid resource code), the function might return something :

private String getStringResourceByName(String aString) {
	String packageName = getPackageName();
	int resId = getResources()
			.getIdentifier(aString, "string", packageName);
	if (resId == 0) {
		return aString;
	} else {
		return getString(resId);
	}
}

Solution 6 - Android

Best Approach

App.getRes().getString(R.string.some_id)

Will work Everywhere (Utils, Models also).

I have read all the answers, all answers can make your work done.

  • You can use getString(R.string.some_string_id) in both Activity or Fragment.
  • You can use Context.getString(R.string.some_string_id) where you don't have direct access to getString() method. Like Dialog.

Problem

When you don't have Context access, like a method in your Util class.

Assume below method without Context.

public void someMethod(){
    ...
    // can't use getResource() or getString() without Context.
}

Now you will pass Context as a parameter in this method and use getString().

public void someMethod(Context context){
    ...
    context.getString(R.string.some_id);
}

What i do is

public void someMethod(){
    ...
    App.getAppResources().getString(R.string.some_id)
}

What? It is very simple to use anywhere in your app!

So here is a solution by which you can access resources from anywhere like Util class .

import android.app.Application;
import android.content.res.Resources;

public class App extends Application {
    private static Resources resources;

    @Override
    public void onCreate() {
        super.onCreate();

        resources = getResources();
    }

    public static Resources getAppResources() {
        return resources;
    }

}

Add name field to your manifest.xml <application tag.

<application
        android:name=".App"
        ...
        >
        ...
    </application>

Now you are good to go. Use App.getAppResources().getString(R.string.some_id) anywhere in app.

Solution 7 - Android

Easier way is to use the getString() function within the activity.

String myString = getString(R.string.mystring);

Reference: http://developer.android.com/guide/topics/resources/string-resource.html

I think this feature is added in a recent Android version, anyone who knows the history can comment on this.

Solution 8 - Android

A simple way to getting resource string from string into a TextView. Here resourceName is the name of resource

int resID = getResources().getIdentifier(resourceName, "string", getPackageName());
textview.setText(resID);

Solution 9 - Android

getResources() works only when you're in Activity or Fragment class.

  • to get access to strings resource everywhere,

use:

Resources.getSystem().getString(android.R.string.somecommonstuff)

Solution 10 - Android

If you don't have an Activity reference, you can use your context in this way:

getContext().getString(R.string.your_string_name);

Solution 11 - Android

In case you are using Kotlin, you can define an extension function as follows:

fun Context.getStringResourceByName(stringName: String): String? {
    val resId = resources.getIdentifier(stringName, "string", packageName)
    return getString(resId)
}

And then simply use it. For example, in a Puzzles app I set the Activity title according to the image file name:

val stringName = "${folderName}_${assetName.substringBefore(".")}"
title = getStringResourceByName(stringName)

In this example I am reading string resources based on dynamic names.

Solution 12 - Android

In Kotlin, Leverage Extension functions 

fun Context.getStringByName(name: String): String {
    return getString(resources.getIdentifier(name, "string", packageName))
}

Solution 13 - Android

There is also a set of predefined Android strings such as "Ok", "Cancel" and many others - so you don't have to declare all. They're available simply by:

getString(android.R.string.ok)

(In this case, "Ok" string). BTW there are also other Android resources available like for example icons images etc.

Solution 14 - Android

String myString = getString(R.string.mystring);

easy way

Solution 15 - Android

If you wannt get it inside an activity or fragmnet, then:

getContext().getResources().getString(R.string.string_name);

If you want to get it from a class outside of activity or fragment where you don't have the activity context then use application context:

getApplicationContext().getResources().getString(R.string.string_name);

Solution 16 - Android

You can try this in an Activity:

getResources().getString(R.string.your string name);

In other situations like fragments,... use

getContext().getResources().getString(R.string.your string name);

Solution 17 - Android

To safe, you should add: mContext.getResources().getString(R.string.your_string);

mContext can be: context in onAttach() of Fragment or this of Activity.

Solution 18 - Android

R.string.<string_name>

Use that line directly in your java file. Keep it simple.

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionIvanView Question on Stackoverflow
Solution 1 - Androiduser658042View Answer on Stackoverflow
Solution 2 - AndroidleonvianView Answer on Stackoverflow
Solution 3 - AndroidkonmikView Answer on Stackoverflow
Solution 4 - AndroidTOUDIdelView Answer on Stackoverflow
Solution 5 - AndroidMiguel RiveroView Answer on Stackoverflow
Solution 6 - AndroidKhemraj SharmaView Answer on Stackoverflow
Solution 7 - AndroidEren YilmazView Answer on Stackoverflow
Solution 8 - AndroidMuhammad AdilView Answer on Stackoverflow
Solution 9 - AndroidHarshit JainView Answer on Stackoverflow
Solution 10 - AndroidNammen8View Answer on Stackoverflow
Solution 11 - AndroidJCarlosRView Answer on Stackoverflow
Solution 12 - AndroidM.MuzammilView Answer on Stackoverflow
Solution 13 - AndroidforsbergView Answer on Stackoverflow
Solution 14 - AndroidAvinashView Answer on Stackoverflow
Solution 15 - Androidrohegde7View Answer on Stackoverflow
Solution 16 - AndroidM Shafaei NView Answer on Stackoverflow
Solution 17 - AndroidO Thạnh LdtView Answer on Stackoverflow
Solution 18 - AndroidOwais YosufView Answer on Stackoverflow