add onclick function to a submit button

OnclickSubmit

Onclick Problem Overview


I'm just learning javascript and php. I created a contact form and I'd like the submit button to accomplish two things when I press it:

  1. submit the data to me (this part is working)
  2. read my onclick function (this part is not working)

<input id="submit" name="submit" type="submit" value="Submit" onclick="eatFood()">

<?php
if ($_POST['submit']) {
 ////????? 
}
?>

I'm sending the data to my email, and so I get that. But the onclick function doesn't seem to work. I tried reviewing https://stackoverflow.com/questions/5356011/add-onclick-function-for-submit-button but it didn't help.

Onclick Solutions


Solution 1 - Onclick

I need to see your submit button html tag for better help. I am not familiar with php and how it handles the postback, but I guess depending on what you want to do, you have three options:

  1. Getting the handling onclick button on the client-side: In this case you only need to call a javascript function.

function foo() {
   alert("Submit button clicked!");
   return true;
}

<input type="submit" value="submit" onclick="return foo();" />

  1. If you want to handle the click on the server-side, you should first make sure that the form tag method attribute is set to post:

     <form method="post">
    
  2. You can use onsubmit event from form itself to bind your function to it.

<form name="frm1" method="post" onsubmit="return greeting()">
    <input type="text" name="fname">
    <input type="submit" value="Submit">
</form>

Solution 2 - Onclick

html:

<form method="post" name="form1" id="form1">    
    <input id="submit" name="submit" type="submit" value="Submit" onclick="eatFood();" />
</form>

Javascript: to submit the form using javascript

function eatFood() {
document.getElementById('form1').submit();
}

to show onclick message

function eatFood() {
alert('Form has been submitted');
}

Solution 3 - Onclick

if you need to do something before submitting data, you could use form's onsubmit.

<form method=post onsubmit="return doSomething()">
  <input type=text name=text1>
  <input type=submit>
</form>

Solution 4 - Onclick

I have this code:

<html>
<head>
<SCRIPT type=text/javascript>
function deshabilitarBoton() {     
    document.getElementById("boton").style.display = 'none';
    document.getElementById("envio").innerHTML ="<br><img src='img/loading.gif' width='16' height='16' border='0'>Generando...";     
    return true;
} 
</SCRIPT>
<title>untitled</title>
</head>
<body>
<form name="form" action="ok.do" method="post" >
<table>
<tr>
<td>Fecha inicio:</td>
<td><input type="TEXT" name="fecha_inicio" id="fecha_inicio"  /></td>
</tr>
</table>
<div id="boton">
   <input type="submit" name="event" value="Enviar" class="button" onclick="return deshabilitarBoton()" />
</div>
<div id="envio">
</div>
</form>
</body>
</html>

Solution 5 - Onclick

  1. Create a hidden button with id="hiddenBtn" and type="submit" that do the submit
  2. Change current button to type="button"
  3. set onclick of the current button call a function look like below:
function foo() {
    // do something before submit
    ...
    // trigger click event of the hidden button
    $('#hinddenBtn').trigger("click");
}

Solution 6 - Onclick

<button type="submit" name="uname" value="uname" onclick="browserlink(ex.google.com,home.html etc)or myfunction();"> submit</button>

if you want to open a page on the click of a button in HTML without any scripting language then you can use above code.

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestioncatchmikeyView Question on Stackoverflow
Solution 1 - OnclickmanmanView Answer on Stackoverflow
Solution 2 - Onclickstash_manView Answer on Stackoverflow
Solution 3 - OnclickRoozbeh ZabihollahiView Answer on Stackoverflow
Solution 4 - OnclickanghelizView Answer on Stackoverflow
Solution 5 - OnclicknguyentaijsView Answer on Stackoverflow
Solution 6 - OnclickPratibha kumari bhaskarView Answer on Stackoverflow