Add another tuple to a tuple of tuples
PythonTuplesPython Problem Overview
I have the following tuple of tuples:
my_choices=(
('1','first choice'),
('2','second choice'),
('3','third choice')
)
and I want to add another tuple to the start of it
another_choice = ('0', 'zero choice')
How can I do this?
the result would be:
final_choices=(
('0', 'zero choice')
('1','first choice'),
('2','second choice'),
('3','third choice')
)
Python Solutions
Solution 1 - Python
Build another tuple-of-tuples out of another_choice, then concatenate:
final_choices = (another_choice,) + my_choices
Alternately, consider making my_choices a list-of-tuples instead of a tuple-of-tuples by using square brackets instead of parenthesis:
my_choices=[
('1','first choice'),
('2','second choice'),
('3','third choice')
]
Then you could simply do:
my_choices.insert(0, another_choice)
Solution 2 - Python
Don't convert to a list and back, it's needless overhead. + concatenates tuples.
>>> foo = ((1,),(2,),(3,))
>>> foo = ((0,),) + foo
>>> foo
((0,), (1,), (2,), (3,))
Solution 3 - Python
Alternatively, use the tuple concatenation
i.e.
final_choices = (another_choice,) + my_choices
Solution 4 - Python
What you have is a tuple of tuples, not a list of tuples. Tuples are read only. Start with a list instead.
>>> my_choices=[
... ('1','first choice'),
... ('2','second choice'),
... ('3','third choice')
... ]
>>> my_choices.insert(0,(0,"another choice"))
>>> my_choices
[(0, 'another choice'), ('1', 'first choice'), ('2', 'second choice'), ('3', 'third choice')]
list.insert(ind,obj) inserts obj at the provided index within a list... allowing you to shove any arbitrary object in any position within the list.