Access the http response headers in a WebView?

Android

Android Problem Overview


Is there a way to view the http response headers in an Activity once a web page has been loaded in a WebView? Seems like this should be possible, but I can't find any methods that expose the headers.

Android Solutions


Solution 1 - Android

Neither WebView nor WebViewClient provide methods to do that, Though, you can try to implement that manually. You can do something like this:

private WebView webview;
public void onCreate(Bundle icicle){
    // bla bla bla

    // here you initialize your webview
    webview = new WebView(this);
    webview.setWebViewClient(new YourWebClient());
}

// this will be the webclient that will manage the webview
private class YourWebClient extends WebViewClient{

    // you want to catch when an URL is going to be loaded
    public boolean  shouldOverrideUrlLoading  (WebView  view, String  urlConection){
        // here you will use the url to access the headers.
        // in this case, the Content-Length one
        URL url;
        URLConnection conexion;
        try {
            url = new URL(urlConection);
            conexion = url.openConnection();
            conexion.setConnectTimeout(3000);
            conexion.connect();
            // get the size of the file which is in the header of the request
            int size = conexion.getContentLength();
        }
 

        // and here, if you want, you can load the page normally
        String htmlContent = "";
        HttpGet httpGet = new HttpGet(urlConection);
        // this receives the response
        HttpResponse response;
        try {
            response = httpClient.execute(httpGet);
            if (response.getStatusLine().getStatusCode() == 200) {
                // la conexion fue establecida, obtener el contenido
                HttpEntity entity = response.getEntity();
                if (entity != null) {
                    InputStream inputStream = entity.getContent();
                    htmlContent = convertToString(inputStream);
                }
            }
         } catch (Exception e) {}

         webview.loadData(htmlContent, "text/html", "utf-8");
         return true;
    }

    public String convertToString(InputStream inputStream){
        StringBuffer string = new StringBuffer();
        BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));
        String line;
        try {
            while ((line = reader.readLine()) != null) {
                string.append(linea + "\n");
            }
        } catch (IOException e) {}
        return string.toString();
    }
}

I can't test it right now, but that's basically what you could do (it's very crazy though :).

Solution 2 - Android

inspired by Cristian answer I needed to intercept AJAX calls webview is doing, where I needed to intercept response headers to get some information (cart item count in e-commerce app), which I needed to leverage in app. As the app is using okhttp I've ended up doing this and it's working:

        @TargetApi(Build.VERSION_CODES.LOLLIPOP)
        @Override
        public WebResourceResponse shouldInterceptRequest(WebView view, WebResourceRequest request) {
            Log.i(TAG,"shouldInterceptRequest path:"+request.getUrl().getPath());
            WebResourceResponse returnResponse = null;
            if (request.getUrl().getPath().startsWith("/cart")) { // only interested in /cart requests
                returnResponse = super.shouldInterceptRequest(view, request);
                Log.i(TAG,"cart AJAX call - doing okRequest");
                Request okRequest = new Request.Builder()
                        .url(request.getUrl().toString())
                        .post(null)
                        .build();
                try {
                    Response okResponse = app.getOkHttpClient().newCall(okRequest).execute();
                    if (okResponse!=null) {
                        int statusCode = okResponse.code();
                        String encoding = "UTF-8";
                        String mimeType = "application/json";
                        String reasonPhrase = "OK";
                        Map<String,String> responseHeaders = new HashMap<String,String>();
                        if (okResponse.headers()!=null) {
                            if (okResponse.headers().size()>0) {
                                for (int i = 0; i < okResponse.headers().size(); i++) {
                                    String key = okResponse.headers().name(i);
                                    String value = okResponse.headers().value(i);
                                    responseHeaders.put(key, value);
                                    if (key.toLowerCase().contains("x-cart-itemcount")) {
                                        Log.i(TAG,"setting cart item count");
                                        app.setCartItemsCount(Integer.parseInt(value));
                                    }
                                }
                            }
                        }
                        InputStream data = new ByteArrayInputStream(okResponse.body().string().getBytes(StandardCharsets.UTF_8));
                        Log.i(TAG, "okResponse code:" + okResponse.code());
                        returnResponse = new WebResourceResponse(mimeType,encoding,statusCode,reasonPhrase,responseHeaders,data);
                    } else {
                        Log.w(TAG,"okResponse fail");
                    }
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return returnResponse;
        }

I hope this may be helpful to others and if somebody has a suggestions for improvement I would be grateful. Unfortunately it's compatible only with LOLLIPOP and higher as from this version you can access/return headers using WebResourceRequest, which was needed for my case.

Solution 3 - Android

You should be able to control all your headers by skipping loadUrl and writing your own loadPage using Java's HttpURLConnection. Then view the headers, do your thing, and use the webview's loadData to display the response.

Solution 4 - Android

There is an alternative solution if you're targeting at least Kit-Kat, even though this wouldn't show the headers in the Activity but rather in Chrome. You can simply follow this short guide on how to remotely debug Webviews.

The 2 key points are, first, to enable WebView debugging in you app

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT) {
    WebView.setWebContentsDebuggingEnabled(true);
}

And then open chrome://inspect in a Chrome tab in a computer. Once you connect your phone via USB to the computer, you will see your app's WebView in the list of debuggable devices

Solution 5 - Android

you can use OkHttp:

private fun handleRequestViaOkHttp(url: String) {

            var httpClient = OkHttpClient()

            thread {
                try {
                    val request = Request.Builder().url(url).build()
                    print("Request: $request")
                    val response = httpClient.newCall(request).execute()
                    println("Response: " + response.headers().toString())
                } catch (e: Exception) {}
            }
        }

you should call it inside this method:

override fun shouldInterceptRequest(view: WebView?, request: WebResourceRequest?): WebResourceResponse? {

                handleRequestViaOkHttp(webViewUrl.value.toString())
                return super.shouldInterceptRequest(view, request)
        }

Solution 6 - Android

As the accepted answer will only work with HttpGet, here is a trick thet currently I'm using (at this time it seems to work)

In onPageFinished handler, if there is an error, the title of the page will be like "ERROR_NUM - ERROR_DESCRIPTION", like "500 - Internal Server Error", so all I do is to get title from webview in the function, and then check the title.

view.getTitle()

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestiontronmanView Question on Stackoverflow
Solution 1 - AndroidCristianView Answer on Stackoverflow
Solution 2 - AndroidursimonView Answer on Stackoverflow
Solution 3 - AndroidR Earle HarrisView Answer on Stackoverflow
Solution 4 - AndroidNicolás Carrasco-StevensonView Answer on Stackoverflow
Solution 5 - AndroidDiogo SequeiraView Answer on Stackoverflow
Solution 6 - AndroidMehran SHView Answer on Stackoverflow