Access object child properties using a dot notation string

JavascriptJquery

Javascript Problem Overview


I'm temporarily stuck with what appears to be a very simple JavaScript problem, but maybe I'm just missing the right search keywords!

Say we have an object

var r = { a:1, b: {b1:11, b2: 99}};

There are several ways to access the 99:

r.b.b2
r['b']['b2']

What I want is to be able to define a string

var s = "b.b2";

and then access the 99 using

r.s or r[s] //(which of course won't work)

One way is to write a function for it that splits the string on dot and maybe recursively/iteratively gets the property. But is there any simpler/more efficient way? Anything useful in any of the jQuery APIs here?

Javascript Solutions


Solution 1 - Javascript

Here's a naive function I wrote a while ago, but it works for basic object properties:

function getDescendantProp(obj, desc) {
    var arr = desc.split(".");
    while(arr.length && (obj = obj[arr.shift()]));
    return obj;
}

console.log(getDescendantProp(r, "b.b2"));
//-> 99

Although there are answers that extend this to "allow" array index access, that's not really necessary as you can just specify numerical indexes using dot notation with this method:

getDescendantProp({ a: [ 1, 2, 3 ] }, 'a.2');
//-> 3

Solution 2 - Javascript

split and reduce while passing the object as the initalValue

Update (thanks to comment posted by TeChn4K)

With ES6 syntax, it is even shorter

var r = { a:1, b: {b1:11, b2: 99}};
var s = "b.b2";

var value = s.split('.').reduce((a, b) => a[b], r);

console.log(value);

Old version

var r = { a:1, b: {b1:11, b2: 99}};
var s = "b.b2";

var value = s.split('.').reduce(function(a, b) {
  return a[b];
}, r);

console.log(value);

Solution 3 - Javascript

You can use lodash get() and set() methods.

Getting

var object = { 'a': [{ 'b': { 'c': 3 } }] };

_.get(object, 'a[0].b.c');
// → 3

Setting

var object = { 'a': [{ 'b': { 'c': 3 } }] };

_.set(object, 'a[0].b.c', 4);
console.log(object.a[0].b.c);
// → 4

Solution 4 - Javascript

If it's possible in your scenario that you could put the entire array variable you're after into a string you could use the eval() function.

var r = { a:1, b: {b1:11, b2: 99}};
var s = "r.b.b2";
alert(eval(s)); // 99

I can feel people reeling in horror

Solution 5 - Javascript

Extending @JohnB's answer, I added a setter value as well. Check out the plunkr at

http://plnkr.co/edit/lo0thC?p=preview

enter image description here

function getSetDescendantProp(obj, desc, value) {
  var arr = desc ? desc.split(".") : [];

  while (arr.length && obj) {
    var comp = arr.shift();
    var match = new RegExp("(.+)\\[([0-9]*)\\]").exec(comp);

    // handle arrays
    if ((match !== null) && (match.length == 3)) {
      var arrayData = {
        arrName: match[1],
        arrIndex: match[2]
      };
      if (obj[arrayData.arrName] !== undefined) {
        if (typeof value !== 'undefined' && arr.length === 0) {
          obj[arrayData.arrName][arrayData.arrIndex] = value;
        }
        obj = obj[arrayData.arrName][arrayData.arrIndex];
      } else {
        obj = undefined;
      }

      continue;
    }

    // handle regular things
    if (typeof value !== 'undefined') {
      if (obj[comp] === undefined) {
        obj[comp] = {};
      }

      if (arr.length === 0) {
        obj[comp] = value;
      }
    }

    obj = obj[comp];
  }

  return obj;
}

Solution 6 - Javascript

This is the simplest i could do:

var accessProperties = function(object, string){
   var explodedString = string.split('.');
   for (i = 0, l = explodedString.length; i<l; i++){
      object = object[explodedString[i]];
   }
   return object;
}
var r = { a:1, b: {b1:11, b2: 99}};

var s = "b.b2";
var o = accessProperties(r, s);
alert(o);//99

Solution 7 - Javascript

you could also do

var s = "['b'].b2";
var num = eval('r'+s);

Solution 8 - Javascript

Here is an extension of Andy E's code, that recurses into arrays and returns all values:

function GetDescendantProps(target, pathString) {
    var arr = pathString.split(".");
    while(arr.length && (target = target[arr.shift()])){
        if (arr.length && target.length && target.forEach) { // handle arrays
            var remainder = arr.join('.');
            var results = [];
            for (var i = 0; i < target.length; i++){
                var x = this.GetDescendantProps(target[i], remainder);
                if (x) results = results.concat(x);
            }
            return results;
        }
    }
    return (target) ? [target] : undefined; //single result, wrap in array for consistency
}

So given this target:

var t = 
{a:
    {b: [
            {'c':'x'},
            {'not me':'y'},
            {'c':'z'}
        ]
    }
};

We get:

GetDescendantProps(t, "a.b.c") === ["x", "z"]; // true

Solution 9 - Javascript

I don't know a supported jQuery API function but I have this function:

	var ret = data; // Your object
	var childexpr = "b.b2"; // Your expression
	
	if (childexpr != '') {
		var childs = childexpr.split('.');
		var i;
    	for (i = 0; i < childs.length && ret != undefined; i++) {
    		ret = ret[childs[i]];
    	}
	}

	return ret;

Solution 10 - Javascript

I've extended Andy E's answer, so that it can also handle arrays:

function getDescendantProp(obj, desc) {
    var arr = desc.split(".");

    //while (arr.length && (obj = obj[arr.shift()]));

    while (arr.length && obj) {
        var comp = arr.shift();
        var match = new RegExp("(.+)\\[([0-9]*)\\]").exec(comp);
        if ((match !== null) && (match.length == 3)) {
            var arrayData = { arrName: match[1], arrIndex: match[2] };
            if (obj[arrayData.arrName] != undefined) {
                obj = obj[arrayData.arrName][arrayData.arrIndex];
            } else {
                obj = undefined;
            }
        } else {
            obj = obj[comp]
        }
    }

    return obj;
}

There are probably more efficient ways to do the Regex, but it's compact.

You can now do stuff like:

var model = {
    "m1": {
        "Id": "22345",
        "People": [
            { "Name": "John", "Numbers": ["07263", "17236", "1223"] },
            { "Name": "Jenny", "Numbers": ["2", "3", "6"] },
            { "Name": "Bob", "Numbers": ["12", "3333", "4444"] }
         ]
    }
}

// Should give you "6"
var x = getDescendantProp(model, "m1.People[1].Numbers[2]");

Solution 11 - Javascript

Performance tests for Andy E's, Jason More's, and my own solution are available at http://jsperf.com/propertyaccessor. Please feel free to run tests using your own browser to add to the data collected.

The prognosis is clear, Andy E's solution is the fastest by far!

For anyone interested, here is the code for my solution to the original question.

function propertyAccessor(object, keys, array) {
    /*
    Retrieve an object property with a dot notation string.
    @param  {Object}  object   Object to access.
    @param  {String}  keys     Property to access using 0 or more dots for notation.
    @param  {Object}  [array]  Optional array of non-dot notation strings to use instead of keys.
    @return  {*}
    */
    array = array || keys.split('.')

    if (array.length > 1) {
        // recurse by calling self
        return propertyAccessor(object[array.shift()], null, array)
    } else {
        return object[array]
    }
}

Solution 12 - Javascript

Short answer: No, there is no native .access function like you want it. As you correctly mentioned, you would have to define your own function which splits the string and loops/checks over its parts.

Of course, what you always can do (even if its considered bad practice) is to use eval().

Like

var s = 'b.b2';

eval('r.' + s); // 99

Solution 13 - Javascript

Here is a a little better way then @andy's answer, where the obj (context) is optional, it falls back to window if not provided..

function getDescendantProp(desc, obj) {
    obj = obj || window;
    var arr = desc.split(".");
    while (arr.length && (obj = obj[arr.shift()]));
    return obj;
};

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionmsanjayView Question on Stackoverflow
Solution 1 - JavascriptAndy EView Answer on Stackoverflow
Solution 2 - JavascriptAmmarCSEView Answer on Stackoverflow
Solution 3 - JavascriptMatheus Dal'PizzolView Answer on Stackoverflow
Solution 4 - JavascriptRory McCrossanView Answer on Stackoverflow
Solution 5 - JavascriptJason MoreView Answer on Stackoverflow
Solution 6 - JavascriptNicola PeluchettiView Answer on Stackoverflow
Solution 7 - JavascriptManuel van RijnView Answer on Stackoverflow
Solution 8 - JavascriptIain BallardView Answer on Stackoverflow
Solution 9 - JavascriptFerran BasoraView Answer on Stackoverflow
Solution 10 - JavascriptJohnBView Answer on Stackoverflow
Solution 11 - Javascriptuser2646368View Answer on Stackoverflow
Solution 12 - JavascriptjAndyView Answer on Stackoverflow
Solution 13 - JavascriptadardesignView Answer on Stackoverflow